Python：通过引用传递套接字

Question

我是python的新手，我必须在python中编写我的第一个任务。我保证在完成这一步之后我会学习它，但我现在需要你的帮助。

我的代码，目前看起来是这样的：

comSocket.send("\r") 
sleep(1) 
comSocket.send("\r") 
sleep(2) 
comSocket.settimeout(8) 
try: 
    comSocket.recv(256) 
except socket.timeout: 
    errorLog("[COM. ERROR] Station took too long to reply. \n") 
    comSocket.shutdown(1) 
    comSocket.close() 
    sys.exit(0) 

comSocket.send("\r\r") 
sleep(2) 
comSocket.settimeout(8) 
try: 
    comSocket.recv(256) 
except socket.timeout: 
    errorLog("[COM. ERROR] Station took too long to reply. \n") 
    comSocket.shutdown(1) 
    comSocket.close() 
    sys.exit(0) 

errorLog是另一种方法。我想通过制定一种新方法来重写这段代码，以便我可以通过message，参考socket，然后return从套接字收到的信息。

任何帮助？

谢谢:)

Answer 1

简单的解决办法是

def socketCom(comSocket, length, message, time): 
    comSocket.send(message) 
    comSocket.settimeout(8) 
    if (time != 0): 
     sleep(time) 
    try: 
     rawData = comSocket.recv(length) 
    except socket.timeout: 
     errorLog("[COM. ERROR] Station took too long to reply. \n") 
     comSocket.shutdown(1) 
     comSocket.close() 
     sys.exit(0) 

    return rawData 

Answer 2

来猜测你想要什么：

def send_and_receive(message, socket): 
    socket.send(message) 
    return socket.recv(256) # number is timeout 

然后把你的try:except:在你调用此方法。

Answer 3

你应该做一个类来管理你的错误，并且这个类需要扩展一个你正在使用的comSocket实例，在你放入errorLog函数的那个​​类中。 事情是这样的：

class ComunicationSocket(socket): 
    def errorLog(self, message): 
     # in this case, self it's an instance of your object comSocket, 
     # therefore your "reference" 
     # place the content of errorLog function 
     return True # Here you return what you received from socket 

本

现在只有你所要做的实例化ComunicationSocket什么：

comSocket = ComunicationSocket() 
try: 
    comSocket.recv(256) 
except socket.timeout: 
    # Uses the instance of comSocket to log the error 
    comSocket.errorLog("[COM. ERROR] Station took too long to reply. \n") 
    comSocket.shutdown(1) 
    comSocket.close() 
    sys.exit(0) 

希望，帮助，你不发表您的功能错误日志的内容，所以我发表了你应该把它放在哪里的评论。这是做事的一种方式。希望有所帮助。