我提取JSON值值,但总是收到一个空的结果,当我回显值获取从JSON字符串
$json='[[{"transTime":"2013-10-23 17:30:42","Forename":"Ian","Surname":"Graham","Address Line 1":"RG412GX"}]]';
$obj2 = json_decode($json, true);
$displayName = $obj2->Surname;
echo"$displayName";
我提取JSON值值,但总是收到一个空的结果,当我回显值获取从JSON字符串
$json='[[{"transTime":"2013-10-23 17:30:42","Forename":"Ian","Surname":"Graham","Address Line 1":"RG412GX"}]]';
$obj2 = json_decode($json, true);
$displayName = $obj2->Surname;
echo"$displayName";
试试这个:
<?php
$json='[[{"transTime":"2013-10-23 17:30:42","Forename":"Ian","Surname":"Graham","Address Line 1":"RG412GX"}]]';
$obj2 = json_decode($json, true);
$displayName = $obj2[0][0]['Surname'];
echo "$displayName";
?>
你必须在其他一个一个对象在这个JSON字符串
$json='[[{"transTime":"2013-10-23 17:30:42","Forename":"Ian","Surname":"Graham","Address Line 1":"RG412GX"}]]';
$obj2 = json_decode($json);
print_r($obj2);
这应该是这样的:
$json='[[{"transTime":"2013-10-23 17:30:42","Forename":"Ian","Surname":"Graham","Address Line 1":"RG412GX"}]]';
$obj2 = json_decode($json, true);
$displayName = $obj2->Surname;
echo"$displayName";
你混淆/弥补变量名...
有你所提供的代码的几个问题。 首先,您的json文本存储在$json
中,但您尝试解码$xmlresponse
。我想这只是一个复制/粘贴错误,但。 其次,尽管您明确强制json_decode
将对象解码为关联数组,但您仍尝试使用对象语法访问姓氏。第三,json提供了一个数组中的一个对象的数组。您忽略响应的嵌套结构。
试试这个:
$json='[[{"transTime":"2013-10-23 17:30:42","Forename":"Ian","Surname":"Graham","Address Line 1":"RG412GX"}]]';
$response = json_decode($json);
$displayName = $response[0][0]->Surname;
echo $displayName;
那是什么'$ xmlresponse'? –
$ xmlresponse应该是$ json吗?美元价值从何而来? – Jompper
这需要进行基本的调试。当你做一个'print_r($ obj2);'时,你会得到什么? –