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在下面的代码我试图实现全选functionality.when我clcik上选择的所有复选框的复选框命名为STS没有得到selected.what我做错了选择所有功能复选框
$(document).ready(function() {
$("#selectall").click(function()
{
var checked_status = this.checked;
$(".sts").each(function()
{
this.checked = checked_status;
});
});
});
var ele1 ='<table cellpadding="0" cellspacing="0" border="1" ><tr><th style="width:100px;" ><p align="center">Select all students</p><p align="center"><input type="checkbox" name="sts" class="sts" id="selectall" /></p></th><th><p align="center">Student name</p></th><th><p align="center">Select Grade</p></th><th><p align="center">Certificates</p></th></tr>';
for(var l=0;l<data.studentarr.length;l++)
{
ele1 += '<tr id="s_r_' + data.studentarr[l].id + '" class="students1"><td align="center" style="width:100px;"><input type="checkbox" class="sts" name="sts" /></td><td align="center">' + data.studentarr[l].name +'</td><td align="center">' + getgrade_values(data.studentarr[l].id) + '</td><td>' + data.studentarr[l].download_link + '</td></tr>';
}
ele1 += "</table>";
$('#student_table').append(ele1);
'的cellpadding = “0” CELLSPACING = “0” BORDER = “1”' - 我们有CSS现在。 – ThiefMaster 2011-06-06 06:42:32
哈哈哈哈:)复制粘贴的结果 – Rajeev 2011-06-06 06:45:25