错误试图通过套接字传递（大）图像在python

我试图越过较小的图像蟒蛇插座的图像，它工作正常，但对于更大的图像提示错误为错误试图通过套接字传递（大）图像在python

socket.error：[错误10040 ]在数据报套接字上发送的消息大于内部消息缓冲器或某种其它网络的限制，或用于接收数据报的缓冲液比数据报

较小我使用

socket.socket(socket.AF_INET, socket.SOCK_DGRAM)

感谢您的任何线索。

我尝试使用SOCK_STREAM，它不工作..它只是说我开始...并挂出。没有输出。它没有出来发送功能

import thread 
import socket 
import ImageGrab 

class p2p: 
    def __init__(self): 
     socket.setdefaulttimeout(50) 
     #send port 
     self.send_port = 3000 
     #receive port 
     self.recv_port=2000 

     #OUR IP HERE 
     self.peerid = '127.0.0.1:' 
     #DESTINATION 
     self.recv_peers = '127.0.0.1' 

     #declaring sender socket 
     self.socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM) 
     self.socket.bind(('127.0.0.1', self.send_port)) 
     self.socket.settimeout(50) 

     #receiver socket 
     self.serverSocket=socket.socket(socket.AF_INET, socket.SOCK_STREAM) 
     self.serverSocket.bind(('127.0.0.1', self.recv_port)) 
     self.serverSocket.settimeout(50) 

     #starting thread for reception 
     thread.start_new_thread(self.receiveData,()) 

     #grabbing screenshot 
     image = ImageGrab.grab() 
     image.save("c:\\test.jpg") 
     f = open("c:\\ test.jpg", "rb") 
     data = f.read() 
     #sending 
     self.sendData(data) 
     print 'sent...' 
     f.close() 

     while 1: pass 

    def receiveData(self): 
     f = open("c:\\received.png","wb") 
     while 1: 
      data,address = self.serverSocket.recvfrom(1024) 
      if not data: break 
      f.write(data) 
     try: 
      f.close() 
     except: 
      print 'could not save' 
     print "received" 
    def sendData(self,data): 
     self.socket.sendto(data, (self.recv_peers,self.recv_port)) 
if __name__=='__main__': 
    print 'Started......'  
    p2p()

来源

2009-09-19 Xinus