从JsonObject中读取Json字符串android

-1

我有问题;我无法从jsonObject读取内部字符串。它说JsonArray不能转换成JsonObject。从JsonObject中读取Json字符串android

07-26 13:01:31.910 1798-1901/com.example.phuluso.aafs I/System.out: [{"AccommoAddress":{"AddressID":12,"City":"Johannesburg","InfoUrl":null,"Lattitude":"-26.181321","Longitude":"27.99158","PostalCode":2109,"Street":"22 Ararat Str","Town":"Westdene"},"AccommoDetails":null,"AccommoID":1,"AccommoImages":null,"AccommoName":"West Dunes Properties","AccommoType":"Flat","AccredStatus":"ACCREDITED","AddressId":12,"Capacity":9,"Distance":1,"EndDate":"2017-01-01","NearestCampus":"APK","OwnerId":0,"StartDate":"2016-01-01"}]

这是我的JsonArray。我试图从AccommoAddress阅读，但我得到的错误如下：

[{"AccommoAddress":{"AddressID":12,"City":"Johannesburg","InfoUrl":null,"Lattitude":"-26.181321","Longitude":"27.99158","PostalCode":2109,"Street":"22 Ararat Str","Town":"Westdene"},"AccommoDetails":null,"AccommoID":1,"AccommoImages":null,"AccommoName":"West Dunes Properties","AccommoType":"Flat","AccredStatus":"ACCREDITED","AddressId":12,"Capacity":9,"Distance":1,"EndDate":"2017-01-01","NearestCampus":"APK","OwnerId":0,"StartDate":"2016-01-01"}]

这里是我的代码

@Override 
    protected void onPostExecute(String result) { 

     progressDialog.dismiss(); 
     List<AccommoNearAPK> data = new ArrayList<>(); 
     progressDialog.dismiss(); 

     JSONObject jsonResponse = null; 

     try 
     { 
      jsonResponse = new JSONObject(result); 
      JSONArray jsonMainNode = jsonResponse.optJSONArray("AccommoAddress"); 

      /*********** Process each JSON Node ************/ 

      int lengthJsonArr = jsonMainNode.length(); 

      for(int i=0; i < lengthJsonArr; i++) 
      { 
       /****** Get Object for each JSON node.***********/ 
       JSONObject jsonChildNode = jsonMainNode.getJSONObject(i); 

       /******* Fetch node values **********/ 
       String name  = jsonChildNode.optString("Street"); 
       String number  = jsonChildNode.optString("City"); 
       String date_added = jsonChildNode.optString("Longitude"); 
       String lat = jsonChildNode.optString("Lattitude"); 

       System.out.print("Street"+ name + "City" +number+ "Long" + date_added+" Lat" + lat); 

       Toast.makeText(MapsActivity.this, date_added + name + number + lat, Toast.LENGTH_LONG).show(); 

      } 

     } catch (JSONException e) { 
      Toast.makeText(MapsActivity.this, e.toString(), Toast.LENGTH_LONG).show(); 
     } 
    } 
}

来源

2016-07-26 Linda

你有数据的JSON数组，并尝试分析它为'新的JSONObject（结果）'似乎很明显 –

-1

你的反应是JSONArray，不是JSONObject，同样，AccommoAddress是JSONObject，不一个JSONArray。因此，您需要将靠近顶部的行更改为以下行：

JSONArray jsonResponse = null; 

try 
{ 
    jsonResponse = new JSONArray(result); 
    JSONObject jsonMainNode = jsonResponse.optJSONObject("AccommoAddress");

来源

2016-07-26 11:26:06

请不要回答这样明显的愚蠢行为 –

“AccommoAddress”是JSONObject而不是JSONArray。这所以不是..

JSONArray jsonMainNode = jsonResponse.optJSONArray("AccommoAddress");

试试这个..

/*String Accommo = jsonResponse.getString("AccommoAddress"); 
JSONObject AccomoAddress = new JSONObject(Accommo);*/ 
//simplifying the above code 
JSONObject Accomoaddress = jsonResponse.optJSONObject("AccomoAddress"); 
String name = AccomoAddress.getString("Street"); 
String number = AccomoAddress.getString("City"); 
String date_added = AccomoAddress.getString("Longitude"); 
String lat = AccomoAddress.getString("Lattitude");

来源

2016-07-26 11:53:05 Suvendu

从JsonObject中读取Json字符串android

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