创建的字母

Question

简单的计数器所以我编写返回的信件比一个超级简单的计数器：

def hasnoe(word): 
    count = 0 
    for letter in word: 
     if letter == 'e': 
      count += 1.0 
    ratio = count/(len(word)) 
    return ratio 

hasnoe('eeeeeeheif') 

但是当我尝试它，电脑没有返回值的 - 是什么呢？

Answer 1

您不能从一个函数返回多个时间。在循环的第一个字母后，您现在返回count，因此它只能是0或1。

所有您需要做什么来解决这个删除return count

def hasnoe(word): 
    count = 0 
    for letter in word: 
     if letter == 'e': 
      count += 1.0 
    ratio = count/(len(word)) 
    return ratio 

>>> hasnoe('eeeeeeheif') 
0.7 

Answer 2

试试这个代码返回两次

def hasnoe(word): 
     count = 0 
     for letter in word: 
      if letter == 'e': 
       count += 1.0 
     ratio = count/(len(word)) 
     return ratio 

    hasnoe('eeeeeeheif') 

Answer 3

你最好的选择将是，如果你想返回一个元组两个数字。

def hasnoe(word): 
    count = 0 
    for letter in word: 
     if letter == 'e': 
      count += 1.0 
    ratio = count/(len(word)) 
    return ratio, count 

ratio, count = hasnoe('eeeeeeheif') 

Answer 4

>>> from collections import Counter 
>>> s = 'eeeeeeheif' 
>>> c = Counter(s) 
>>> c 
Counter({'e': 7, 'i': 1, 'h': 1, 'f': 1}) 
>>> den = float(len(s)) 
>>> freq = dict((k, v/den) for k, v in c.iteritems()) 
>>> freq 
{'i': 0.1, 'h': 0.1, 'e': 0.7, 'f': 0.1}