检查类是相等的两个字符串

Question

之一

是否有可能修改这个不知何故，以便它可以找到表类class1的 * 或 *类类class2？

Info = soup.find('table', {'class' :'class1'}) 

Answer 1

find_all(self, name=None, attrs={}, recursive=True, text=None, limit=None, **kwargs) 

    Extracts a list of Tag objects that match the given 
    criteria. You can specify the name of the Tag and any 
    attributes you want the Tag to have. 

    The value of a key-value pair in the 'attrs' map can be a 
    string, a list of strings, a regular expression object, or a 
    callable that takes a string and returns whether or not the 
    string matches for some custom definition of 'matches'. The 
    same is true of the tag name. 

例如：

>>> from bs4 import BeautifulSoup 
>>> text = ''.join('<table class="class{}"></table>'.format(i) for i in range(10)) 
>>> soup = BeautifulSoup(text) 
>>> 
>>> soup.find_all("table", {"class": ["class1", "class7"]}) 
[<table class="class1"></table>, <table class="class7"></table>] 
>>> import re 
>>> soup.find_all("table", {"class": re.compile("class[17]")}) 
[<table class="class1"></table>, <table class="class7"></table>] 
>>> 
>>> soup.find_all("table", {"class": lambda x: 3*int(x[-1])**2-24*int(x[-1])+17 == -4}) 
[<table class="class1"></table>, <table class="class7"></table>] 

[好吧，最后一个比赛太多了，但你的想法：任何BOOL，返回匹配功能将工作]