参数化测试很适合将不同数据输入到您的测试中。但是,我创建了一个示例计算器,我想为其创建参数化测试。但是,我发现您只能为单个测试创建一组参数化数据。使用多个测试进行参数化junit测试
我已经创建了参数化测试,用于在预期结果中添加2个数字。由于预期结果不同,这些数据将不会与减法一起使用。
是否有可能对每个测试的参数化数据进行加,减,乘和除?
非常感谢您的任何建议,
@RunWith(Parameterized.class)
public class CalculatorModelPresenterTest {
private CalculatorModel mCalculatorModel;
/* Array of tests */
@Parameterized.Parameters
public static Collection<Object[]> data() {
return Arrays.asList(new Object[][]{
{3.0, 4.0, 7.0},
{4.0, 3.0, 7.0},
{8.0, 2.0, 10.0},
{-1.0, 4.0, 3.0},
{3256.0, 4.0, 3260.0}
});
}
private double mNumberOne;
private double mNumberTwo;
private double mExpectedResult;
/* CONSTRUCTOR THAT ASSIGNS THE FIELDS WITH THE TEST DATA */
public CalculatorModelPresenterTest(double numberOne, double numberTwo, double expectedResult) {
mNumberOne = numberOne;
mNumberTwo = numberTwo;
mExpectedResult = expectedResult;
}
/* THIS TEST WILL PASS AS THE TEST DATA IS FOR ADDING */
@Test
public void testAdd() throws Exception {
final double actualResult = mCalculatorModel.add(mNumberOne, mNumberTwo);
assertEquals(actualResult, mExpectedResult, 0);
}
/* HOWEVER, THIS TEST WILL ALWAYS FAIL AS THE TEST DATA IS CUSTOMIZED FOR THE ADD */
@Test
public void testSub() throws Exception {
final double actualResult = mCalculatorModel.sub(mNumberOne, mNumberTwo);
assertEquals(actualResult, mExpectedResult, 0);
}
@Before
public void setUp() throws Exception {
mCalculatorModel = new CalculatorModel();
}
@After
public void tearDown() throws Exception {
mCalculatorModel = null;
}
}
你并不需要设置'mCalculatorModel'到'null'在'tearDown'方法,因为JUnit的每一组参数创建类'CalculatorModelPresenterTest'的新实例。 –