SQL Server查询+加盟结果

我有这样的查询：SQL Server查询+加盟结果

SELECT recipientid AS ID, 
COUNT(*) AS Recieved FROM Inbox 
GROUP BY recipientid 

UNION 

SELECT SenderId, 
COUNT(*) AS [Sent] FROM Inbox 
GROUP BY SenderId

输出：

RecipientID Recieved 

001    3 
001    4 
002    4 
002    2 
003   18 
003   55

我怎么可以重写是这样一种方式，它显示是这样的：

RecipientID Recieved Sent 

001    3  4 
002    4  2 
003   18  55

谢谢。

来源

2013-03-15 k80sg

请指定你是目标的RDBMS通过添加适当的标签（Oracle，SQL Server，MySQL等）。可能会有利用不被普遍支持的语言或产品功能的答案。此外，通过使用特定的RDBMS标记它，您的问题可能会得到更适合回答的人的关注。 – Taryn 2013-03-15 18:27:19

刚加入的子查询：

select a.ID,Received,Sent 
from(
    SELECT recipientid AS ID, 
    COUNT(*) AS Recieved FROM Inbox 
    GROUP BY recipientid 
)a 
full outer join(
    SELECT SenderId as ID, 
    COUNT(*) AS [Sent] FROM Inbox 
    GROUP BY SenderId 
)b 
on (a.ID = b.ID) 
order by a.ID;

注意，这抓住所有的sent和received值的任何收件人或发件人。如果您只想要ID属于收件人和发件人的结果，请执行inner join。

来源

2013-03-15 18:25:24

您希望这是一个完整的外连接，而不是内连接，否则您只会收到发送和接收消息的收件人。 – MattW 2013-03-15 18:26:22

@MattW - 好的电话（虽然这个问题并不完全清楚）。 Lemme编辑... – 2013-03-15 18:26:52

ID在第一个选择行中不明确。 – KekuSemau 2013-03-15 18:27:28

如果它的Postgres，MS SQL或其他支持的CTE -

With Both as 
(
SELECT 
    recipientid AS ID, 
    Count(*) AS Recieved, 
    0 as [Sent] 
FROM Inbox 
GROUP BY recipientid 
UNION 
SELECT 
    SenderId as ID, 
    0 as Recieved, 
    Count(*) AS [Sent] 
FROM Inbox 
GROUP BY SenderId 
) 
SELECT 
    ID, 
    Sum(Received) as [Received], 
    Sum(Sent) as [Sent] 
FROM BOTH 
GROUP BY ID 
ORDER BY 1

来源

2013-03-15 18:26:25

我会一个source列添加到您的查询，并做了简单的数据透视

select ID, 
     max (case when source=1 then Cnt else 0 end) as Received, 
     max (case when source=2 then Cnt else 0 end) as Sent 
from (
    SELECT 1 as Source, 
     recipientid AS ID, 
     COUNT(*) AS Cnt 
    FROM Inbox 
    GROUP BY recipientid 
    UNION 
    SELECT 2 as Source, 
     SenderId, 
     COUNT(*) 
    FROM Inbox 
    GROUP BY SenderId 
) x 
GROUP BY ID

来源

2013-03-15 18:27:19 alzaimar

我可能会建议使用'SUM'而不是'MAX'。 – Taryn 2013-03-15 18:28:36

我想过了，这通常是我所做的（SUM而不是MAX），但内部的两个查询无论如何都是分组的，所以它是安全的......但它可能更清晰......另外，我甚至不需要内心小组 – alzaimar 2013-03-15 18:29:55

假设你有一个users表与ID，你可以做这样的事情：

SELECT 
    users.id, 
    COUNT(sent.senderid) AS sent, 
    COUNT(received.recipientid) AS received 
FROM 
    users 
    LEFT JOIN inbox AS sent ON sent.senderid = users.id 
    LEFT JOIN inbox AS received ON received.recipientid = users.id 
GROUP BY sent.senderid, received.recipientid 
ORDER BY users.id;

来源

2013-03-15 18:44:11 user1936123

SQL Server查询+加盟结果

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