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是否有可能通过将其数据绑定到单个值而不是元组来解压类型?OCaml构造函数解包
# type foo = Foo of int * string;;
type foo = Foo of int * string
# Foo (3; "bar");;
Foo (3; "bar");;
Error: The constructor Foo expects 2 argument(s),
but is applied here to 1 argument(s)
# Foo (3, "bar");;
- : foo = Foo (3, "bar")
# (* Can this possibly work? *)
# let Foo data = Foo (3, "bar");;
let Foo data = Foo (3, "bar");;
Error: The constructor Foo expects 2 argument(s),
but is applied here to 1 argument(s)
# (* Here is the version that I know works: *)
# let Foo (d1, d2) = Foo (3, "bar");;
val d1 : int = 3
val d2 : string = "bar"
这在语法上可行吗?
[使用只有一个元组值的变体类型构造函数]可能的重复(http://stackoverflow.com/questions/9774671/using-a-variant-type-constructor-with-just-one-tuple-value ) – ygrek 2012-04-25 07:48:58