函数内循环

Question

为什么计算机不是x？在它经过循环并找到列表中的某些东西，而不是挑选出来之后，它不应该将该值赋给计算机？

def ComputerMove(gameboard): 
    for x in list: 
     if x not in picked and x in list: 
      computer = x 



list = ("b2", "a1", "c3", "a3", "c1", "a2", "b3", "b1", "c2") 

gameboard = {0:' ', 1:' ', 2:' ', 
     3:' ', 4:' ', 5:' ', 
     6:' ', 7:' ', 8:' ', 
     } 
picked = ("b2", "a1", "c3", "a3") 
ComputerMove(gameboard) 

Answer 1

首先，list是一个类型/ reseved，因此您不能将其用作变量名称。其次，你拥有的是一个元组，而不是一个列表。所以，我转换这些和这段代码似乎工作：

def ComputerMove(gameboard): 
    for x in l: 
     if x not in picked: 
      computer = x 
      return computer # not sure what do you want to do with this value? 



l = ["b2", "a1", "c3", "a3", "c1", "a2", "b3", "b1", "c2"] 

gameboard = {0:' ', 1:' ', 2:' ', 
     3:' ', 4:' ', 5:' ', 
     6:' ', 7:' ', 8:' ', 
     } 
picked = ["b2", "a1", "c3", "a3"] 
ComputerMove(gameboard) 
>>c1