嗨我创建了一个函数,它接受一个可接受的sockFD作为输入并将表示形式的IP地址输出到一个字符串。该函数似乎工作正常,直到我打开包装字符串与inet_ntop返回一个空指针,从而给我我的错误的调用。该错误读取为设备上没有空间,我不明白,因为我有大量的内存和ROM。无论如何波纹管是我正在使用的功能。inet_ntop:设备上没有剩余空间
void getTheirIp(int s, char *ipstr){ // int s is the incoming socketFD, ipstr points the the calling
// functions pointer.
socklen_t len;
struct sockaddr_storage addr;
len = sizeof(addr); //I want to store my address in addr which is sockaddr_storage type
int stat;
stat = getpeername(s, (struct sockaddr*)&addr, &len); // This stores addrinfo in addr
printf("getTheirIP:the value of getpeername %d\n",stat);
// deal with both IPv4 and IPv6:
if ((stat=addr.ss_family) == AF_INET) { // I get the size of the sock first
printf("getTheirIP:the value of addr.ss_family is %d\n",stat);
ipstr = malloc(INET_ADDRSTRLEN); // I allocate memory to store the string
struct sockaddr_in *s = (struct sockaddr_in *)&addr; // I then create the struct sockaddr_in which
// is large enough to hold my address
if(NULL == inet_ntop(AF_INET, &s->sin_addr, ipstr, sizeof(ipstr))){ // I then use inet_ntop to
printf("getTheirIP:the value of inet_ntop is null\n");// retrieve the ip address and store
perror("The problem was"); // at location ipstr
}
} else { // AF_INET6 this is the same as the above except it deals with IPv6 length
ipstr = malloc(INET6_ADDRSTRLEN);
struct sockaddr_in6 *s = (struct sockaddr_in6 *)&addr;
inet_ntop(AF_INET6, &s->sin6_addr, ipstr, sizeof(ipstr));
}
printf("%s",ipstr);
}
我忽略了程序的其余部分,因为它太大而不适合我只想着重于修复这部分。然而,下面我将向你展示我的main()的一部分,它调用这个函数。
newSock = accept(listenSock,(struct sockaddr *)&their_addr,&addr_size);
char *someString;
getTheirIp(newSock,someString);
任何帮助将是伟大的。谢谢!
哦,我明白了,你的意思是我分配了多少内存,而不是地址的实际大小。你是这个意思吗?我认为sizeof()获得了分配的内存量。谢谢!!! – 2012-02-10 22:44:48
老兄你完全统治,它的工作......谢谢再次感谢! – 2012-02-10 22:47:07