Json解析与iPhone中的数组数组的问题？

我有以下JSON作为Json解析与iPhone中的数组数组的问题？

{ 
"meta": { 
    "code": 200 
     }, 
"response": { 
      "deals": [   { 
       "id": 32373, 
      "date_added": "2011-01-13 12:12:50", 
      "end_date": "2011-01-14 10:00:00", 
      "active": 1, 
      "discount": { 
       "raw": 71, 
       "formatted": "71%" 
      }, 
      "price": { 
       "raw": "85.00", 
       "formatted": "$85" 
      }, 
      "value": { 
       "raw": "300.00", 
       "formatted": "$300" 
      }, 
      "purchased": 82, 
      "left": null, 
      "title": "$85 For $300 Babyface Facial At Park Avenue MedSpa", 
      "yipit_title": "71% off Babyface Facial", 
      "url": "http://yipit.com/aff/click/?deal=AvwTADtE&key=F374EFbM", 
      "yipit_url": "http://yipit.com/new-york/livingsocial/85-for-300-babyface-facial-at-park-avenue-medspa/", 
      "images": { 
       "image_big": "http://d22nv2k05ynu7x.cloudfront.net/deal_images/deal/85-for-300-babyface-facial-at-park-avenue-medspa-1294920769_display_image.jpg", 
       "image_small": "http://d22nv2k05ynu7x.cloudfront.net/deal_images/deal/85-for-300-babyface-facial-at-park-avenue-medspa-1294920769_small_image.jpg" 
      }, 
      "division": { 
       "slug": "new-york", 
       "name": "New York", 
       "active": 1, 
       "time_zone_diff": -4, 
       "lat": "40.7142690000000000", 
       "lon": "-74.0059730000000000", 
       "url": "http://yipit.com/new-york/" 
      }, 
      "tags": [ 
       { 
        "name": "Facial", 
        "slug": "facial", 
        "url": "http://yipit.com/new-york/deals/facial/" 
       }, 
       { 
        "name": "Spa", 
        "slug": "spa", 
        "url": "http://yipit.com/new-york/deals/spa/" 
       } 
      ], 
      "business": { 
       "name": "Park Avenue MedSpa", 
       "url": "", 
       "locations": [ 
        { 
         "address": "565 Park Ave", 
         "locality": "New York", 
         "phone": "212-593-8821", 
         "lat": null, 
         "lon": null 
        } 
       ] 
      }, 
      "source": { 
       "name": "LivingSocial", 
       "slug": "livingsocial", 
       "paid": 0, 
       "url": "http://yipit.com/new-york/livingsocial" 
      } 
     } 
    ] 
} 
    }

我使用NSJSONSerialization解析此JSON看起来像我的代码

NSError *jsonError; 
NSMutableDictionary *jsonDictionary = [NSJSONSerialization JSONObjectWithData:responseData options:NSJSONReadingMutableLeaves error:&jsonError]; 
NSMutableArray *resultArray = [[jsonDictionary objectForKey:@"response"] valueForKeyPath:@"deals.business.locations"]; 
self.tempArray = [[NSMutableArray alloc]init]; 
aData = [[Data alloc]initwithName:[[resultArray objectAtIndex:0]valueForKey:@"address"]]; 
[self.tempArray addObject:aData];

，但我的地址值是显示器与等为（“565公园大道”支架）但我只想显示565 Park Ave的值。如何解决这个问题。

当你 的NSLog数组或字典这样的，它写入“字串，是比一个字不再

来源

2012-11-07 Ben10

。别担心，你的数据将只565 Park Ave即使NSLog的写入"565 Park Ave"。

事情是这样的-(NSString*)description处理字符串的两个容器。

来源

2012-11-07 13:38:09

你应该创建一个从JSON ADATA的字符串。ADATA保持“”但是从数据解码的字符串将不

来源

2012-11-07 14:28:19

Json解析与iPhone中的数组数组的问题？

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