我的代码中的名称错误

Question

嘿，我有一个非常简单的问题，但是我希望修复它的所有地方似乎都不起作用。所以对于学校我们必须做到这一点，我们将用户输入保存到excel文件中，并在其中执行Mylist.append（电话）时出现错误，说明电话未定义。任何想法如何解决这个问题？

#Zacharriah Task 3 
import csv 
from IPhone import* 
from Android import* 
import time 

def start(): 
    print('Hello Welcome to the Phone Trouble-Shooter') 
    time.sleep(2) 
    phone = input('Please input what brand of phone you have') 
    if "iphone" in phone: 
     print('Your phone has been identified as an Iphone') 
    elif "android" in phone: 
     print('Your phone has been identifies as an Android') 


file = open("Excel_Task_3.csv", "w", newline = "") 
fileWrite = csv.writer(file,delimiter = ",") 
Mylist = [] 

Mylist.append(phone) 

fileWriter.writerow(Mylist) 

file.close() 

Answer 1

如果代码与发布完全相同，那么phone确实没有在您需要的地方定义。它在功能的范围定义，但在室外使用 - 所以定义有没有phone变量：

def start(): 
    # defined in the function's scope 
    phone = input('Please input what brand of phone you have') 
    # rest of code 


file = open("Excel_Task_3.csv", "w", newline = "") 
fileWrite = csv.writer(file,delimiter = ",") 
Mylist = [] 
# Used outside of the function's scope - it is unrecognized here 
Mylist.append(phone) 

你可以做的是从start返回一个值，然后使用它。喜欢的东西：

def start(): 
    phone = input('Please input what brand of phone you have') 
    # rest of code 
    return phone 

# rest of code 
Mylist = [] 
Mylist.append(start()) 

读Short Description of Python Scoping Rules

Answer 2

phone不是start()功能之外定义。

这里：Mylist.append(phone)

你应该修复它。

可选的解决办法：

def start(): 
    print('Hello Welcome to the Phone Trouble-Shooter') 
    time.sleep(2) 
    phone = input('Please input what brand of phone you have') 
    if "iphone" in phone: 
     print('Your phone has been identified as an Iphone') 
    elif "android" in phone: 
     print('Your phone has been identifies as an Android') 
    return phone # Add this. 


file = open("Excel_Task_3.csv", "w", newline = "") 
fileWrite = csv.writer(file,delimiter = ",") 
Mylist = [] 
phone = start() # Add this. 
Mylist.append(phone) 

fileWriter.writerow(Mylist) 

file.close()