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所以我有一个我正在做一个小型文字冒险店的功能。这里是代码：raw_input每次都会返回相同的内容吗？
def shop():
global p #prompt for raw_input
global gold
global arrows
print"""
You enter the small shop and the man at the counter asks "How can I help?"
"""
print"""
"What would you like to buy?" He asks
You look up at the list of items
Copper Axe - 50G
Copper Sword - 50G
Wooden Bow - 30G
Copper Arrows (20) - 20G
Iron Axe - 100G
Iron Sword - 100G
Iron Arrows (20) - 40G
Steel Axe - 200G
Steel Sword - 200G
Steel Arrows (20) - 80G
or type 'exit' to exit the store
"""
print"You have:"
print inv
op = raw_input(p)
if op == "copper axe" or "Copper axe" or "Copper Axe" or "copper Axe":
if gold < 50:
print"You do not have enough gold"
shop()
else:
gold = gold - 50
inv.append("Copper Axe")
shop()
if op == "copper sword" or "copper Sword" or "Copper sword" or "Copper Sword":
if gold < 50:
print"You do not have enough gold"
shop()
else:
gold = gold - 50
inv.append("Copper Sword")
shop()
elif op == "Wooden bow" or "wooden bow" or "Wooden Bow" or "wooden Bow":
if gold < 30:
print"You do not have enough gold"
shop()
else:
gold = gold - 30
inv.append("Wooden Bow")
if arrows < 10:
print"You should probably buy some arrows"
shop()
elif op == "Copper Arrows" or "copper arrows" or "Copper arrows" or "copper Arrows":
if gold < 20:
print"You do not have enough gold"
shop()
else:
gold = gold - 20
arrows = arrows + 20
inv.append("Copper Arrows: %p" % arrows)
shop()
elif op == "iron axe" or "Iron axe" or "Iron Axe" or "iron Axe":
if gold < 100:
print"You do not have enough gold"
shop()
else:
gold = gold - 100
inv.append("Iron Axe")
shop()
elif op == "iron sword" or "Iron Sword" or "Iron sword" or "iron Sword":
if gold < 100:
print"You do not have enough gold"
shop()
else:
gold = gold - 100
inv.append("Iron Sword")
shop()
elif op == "iron arrows" or "Iron arrows" or "Iron Arrows" or "iron Arrows":
if gold < 40:
print"You do not have enough gold"
shop()
else:
gold = gold - 40
iarrows = iarrows + 20
inv.append("Iron arrows %a" % iarrows)
shop()
elif op == "Steel Axe" or "steel axe" or "Steel axe" or "steel Axe":
if gold < 200:
print"You do not have enough gold"
shop()
else:
gold = gold - 200
inv.append("Steel Axe")
shop()
elif op == "Steel Sword" or "steel sword" or "Steel sword" or "steel Sword":
if gold < 200:
print"You do not have enough gold"
shop()
else:
gold = gold - 200
inv.append("Steel Sword")
shop()
elif op == "Steel Arrows" or "steel arrows" or "Steel arrows" or "steel Arrows":
if gold < 80:
print"You do not have enough gold"
shop()
else:
gold = gold - 80
sarrows = sarrows + 20
inv.append("Steel Arrows - %a" % sarrows)
elif op == "exit" or "Exit":
menu()
else:
synerr() #syntax error function
基本上每次我运行它，不管原始输入是什么，它返回作为铜斧头。像这样：
You enter the small shop and the man at the counter asks "How can I help?"
"What would you like to buy?" He asks
You look up at the list of items
Copper Axe - 50G
Copper Sword - 50G
Wooden Bow - 30G
Copper Arrows (20) - 20G
Iron Axe - 100G
Iron Sword - 100G
Iron Arrows (20) - 40G
Steel Axe - 200G
Steel Sword - 200G
Steel Arrows (20) - 80G
or type 'exit' to exit the store
You have:
[]
>>>fkjas;ldkf
You enter the small shop and the man at the counter asks "How can I help?"
"What would you like to buy?" He asks
You look up at the list of items
Copper Axe - 50G
Copper Sword - 50G
Wooden Bow - 30G
Copper Arrows (20) - 20G
Iron Axe - 100G
Iron Sword - 100G
Iron Arrows (20) - 40G
Steel Axe - 200G
Steel Sword - 200G
Steel Arrows (20) - 80G
or type 'exit' to exit the store
You have:
['Copper Axe']
>>>
那么有谁知道可能是什么原因造成的？