如何让str_replace在printf中工作？

Question

我想要替换printf中的下划线字符。但它可能会遗漏一些东西，因为它不起作用。有谁知道如何解决这一问题？

printf("%s",str_replace($fieldinfo,"_"," ")->name); 

Answer 1

您str_replace函数的代码是错误

str_replace($fieldinfo,"_"," ") 

应该

str_replace("_"," ",$fieldinfo->name) 

Answer 2

Hope this will work.

错误： str_replace($fieldinfo,"_"," ")->name 在这里你不能将字符串或数组视为对象。

注：str_replace返回或者string或array但不object;

printf("%s",str_replace("-","_","some-value")); // SOME_VALUE

echo printf("%s",str_replace("-","_","some-value")); // // some_value10 10字符串的长度

Answer 3

希望这将帮助，

考虑$字段信息有这个值 “sample_value_to_output”

$fieldinfo = "sample_value_to_output"; 

printf("%s",str_replace("_"," ",$fieldinfo)); 

这会输出

sample value to output