我们正在尝试在我们的Web应用程序中使用ESAPI。我们在servlet中有以下功能。ESAPI编码问题
protected void doGet(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/html;charset=UTF-8");
response.setHeader(SearchConstants.CACHE_CONTROL_HEADER,
SearchConstants.MAX_AGE_ZERO);
response.setHeader(SearchConstants.CACHE_CONTROL_HEADER,
SearchConstants.NO_CACHE);
response.setDateHeader(SearchConstants.EXPIRES_HEADER, 0);
response.setHeader(SearchConstants.PRAGMA_HEADER, "no cache");
result = processRequest(request, response);
if (SearchConstants.XSLT_ERROR_MSG.equals(result)) {
LOGGER.error("XSLT ERROR FOR QUERY STRING: "
+ request.getQueryString());
response.sendError(HttpServletResponse.SC_INTERNAL_SERVER_ERROR);
} else if (SearchConstants.SEARCH_PAGE_MISSING_MSG.equals(result)) {
LOGGER.error("NOT FOUND ERROR FOR QUERY STRING: "
+ request.getQueryString());
response.sendError(HttpServletResponse.SC_NOT_FOUND);
} else {
final PrintWriter out = response.getWriter();
out.println(result); // this works
// out.println(ESAPI.encoder().encodeForHTML(result));
}
}
在上面的代码,如果我用out.println(ESAPI.encoder().encodeForHTML(result));
,这实际上打印HTML作为浏览器的文本。即它显示为简单文本<html>
其他内容.. </html>
,而不是呈现html页面。 result
只不过是需要在客户端上获得百分之百的html内容。 我们在这里做错了事。请提供一些指示。我们如何在这里实现编码?