以编程方式从WebView登录

Question

在我的Android应用程序中，我使用Web视图来访问服务器提供的一些Web映射数据。服务器需要一些基于HTTP表单的身份验证才能访问这些数据。由于该网站没有移动版本，显示登录页面（或任何其他页面）看起来很糟糕。不幸的是，现场几乎成为我手中，所以我已经想到了以下做法：

• 使用原生用户界面来收集用户名和密码
• 想到了一个HTTP POST发送这些信息到服务器
• 后收到响应获得服务器发送
• 设置的Cookie到web视图
• 尝试最后访问所需数据的饼干

现在我只是想通过登录阶段。

这是一个可行的解决方案，或只是明显错误，我应该尝试别的？

为了完整性我后下

A.认证部分

private String authenticate() throws Exception 
    { 
     // Create a new HttpClient and Post Header 
      HttpClient httpclient = new DefaultHttpClient(); 
      HttpPost httppost = new HttpPost("http://mySite/login_form"); 

      HttpResponse response = null; 
      BufferedReader in = null; 
      String resultContent = null; 

      try 
      { 
       // Add data 
       List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); 
       nameValuePairs.add(new BasicNameValuePair("came_from", "")); 
       nameValuePairs.add(new BasicNameValuePair("form.submitted", "1")); 
       nameValuePairs.add(new BasicNameValuePair("js_enabled", "0")); 
       nameValuePairs.add(new BasicNameValuePair("cookies_enabled", "")); 
       nameValuePairs.add(new BasicNameValuePair("login_name", "")); 
       nameValuePairs.add(new BasicNameValuePair("pwd_empty", "0")); 
       nameValuePairs.add(new BasicNameValuePair("name", "username")); 
       nameValuePairs.add(new BasicNameValuePair("password", "password")); 

       httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 

       // Create a local instance of cookie store 
       CookieStore cookieStore = new BasicCookieStore(); 
       // Create local HTTP context 
       HttpContext localContext = new BasicHttpContext(); 
       // Bind custom cookie store to the local context 
       localContext.setAttribute(ClientContext.COOKIE_STORE, cookieStore); 
       // Execute HTTP Post Request 
       response = httpclient.execute(httppost,localContext); 

       in = new BufferedReader(new InputStreamReader(response.getEntity().getContent())); 
       StringBuffer sb = new StringBuffer(""); 
       String line = ""; 
       String NL = System.getProperty("line.separator"); 
       while ((line = in.readLine()) != null) 
       { 
       sb.append(line + NL); 
       } 
       in.close(); 
       resultContent = sb.toString(); 
       Log.i("mytag","result :"+resultContent); 

       cookies = new java.util.ArrayList(); 
       cookies = cookieStore.getCookies(); 

      } 
      catch (ClientProtocolException e) 
      { 
       Log.i("mytag","Client protocol exception"); 
      } 
      catch (IOException e) 
      { 
       Log.i("mytag","IOException"); 
      } 
      catch(Exception e) 
      { 
       Log.i("mytag","Exception"); 
       Log.i("mytag",e.toString()); 
      } 


     return resultContent; 

    } 

B.设置cookies和加载所需的页面

private void init() 
{ 
      CookieSyncManager.createInstance(this); 
      CookieManager cookieMan= CookieManager.getInstance(); 
      cookieMan.setAcceptCookie(true); 
      cookies = StartupActivity.listAfter; 

      if(cookies != null) 
      { 
       for (int i = 0; i<cookies.size(); i++) 
       { 
        Cookie cookie = cookies.get(i); 
        cookieMan.setCookie("cookie.getDomain()",cookie.getValue()); 
       } 
      } 
      CookieSyncManager.getInstance().sync(); 

      webView = (WebView)findViewById(R.id.web_view); 
      webView.getSettings().setJavaScriptEnabled(true); 
      webView.getSettings().setBuiltInZoomControls(true); 
      webView.setWebViewClient(new HelloWebViewClient()); 

} 

    protected void onResume() 
    { 
      super.onResume();  

      // test if the we logged in 
      webView.loadUrl("mySite/myDesiredFeature"); 

    } 

加载该页面的结果代码是显示的登录页面表格

Answer 1

1）先尝试使HttpGet请求，获取cookie，然后执行HttpPost。我认为这样你不应该手动添加cookie。 使用一个HttpClient来做到这一点。

2）代替

  in = new BufferedReader(new InputStreamReader(response.getEntity().getContent())); 
      StringBuffer sb = new StringBuffer(""); 
      String line = ""; 
      String NL = System.getProperty("line.separator"); 
      while ((line = in.readLine()) != null) 
      { 
      sb.append(line + NL); 
      } 
      in.close(); 
      resultContent = sb.toString(); 

使用 EntityUtils.toString（response.getEntity（））。