Python，数据库密码

Question

我正在做类的简单数据库，我有密码功能的问题。我无法弄清楚为什么它每次都要求设置密码。我认为问题在于阅读是否已经在基础之内，但我不知道如何解决。

import shelve 
global base,pas 
global magazine_base 
def load_data(): 
    global base 
    global magazine_base 
    magazine_base = shelve.open('magazine_base') 
    if magazine_base.has_key('base'): 
     base = magazine_base['base'] 
     if not base: 
      base = [] 
    else: 
     base = [] 
     magazine_base['base'] = base 

def enterpass(): 
    global base,pas 
    epas=raw_input("Enter password to acces database") 
    for entry in base: 
     while True: 
      if epas == entry['pas']: 

       break 
      else: 
       print "Password incorrect" 

def password(): 
    global base,pas 
    global magazine_base 
    load_data() 

    is_firstopen = True 

    if 'pas' in base: 
     is_firstopen = False 
     enterpass() 
    if is_firstopen: 
     while True: 
      pas=raw_input("This is the first start of database.\nPlease enter the password, min. 5 characters: ") 
      if len(pas)>5: 
       break 
       base += [{'pas':pas}] 
       magazine_base['base'] = base 
       magazine_base.close() 
       print "Password set" 
      else: 
       print "Password too short" 

Answer 1

您有提示要求在无限循环中输入密码。

Answer 2

让我们看一下这个功能：

def enterpass(): 
    global base,pas 
    epas=raw_input("Enter password to acces database") 
    for entry in base: 
     while True: 
      if epas == entry['pas']: 
       break 
      else: 
       print "Password incorrect" 

显然，基础是包含条目的列表。每个条目将是一个有'pas'键的字典。如果'pas'条目与用户密码匹配，则密码有效。我认为如果没有匹配的密码是错误的。这是不是代码做什么，但它试一下：

import sys 

def enter_password(base): 
    """Prompt the user for a password, and validate it against the 
    passwords stored in the entries in base. Permit three tries 
    before terminating the application.""" 

    from getpass import getpass 

    for tries in range(3): 
     userpw = getpass("Enter password to access database: ") 

     for entry in base: 
      if entry['pas'] == userpw: 
       return 

     print "\nInvalid password!\n" 

    print "\nToo many failed password attempts. Goodbye!" 
    sys.exit(1) 

你可以这样调用它：

enter_password(base)