嘿家伙我有一个JPA查询问题。SQL语法有什么问题?
这里的代码片段:
TypedQuery<ViVertragDl> q = entityManager.createQuery("select * from ViVertragDl c where c.id = " + editContract.getId(), ViVertragDl.class);
List<ViVertragDl> jpaContractDls = q.getResultList();
和GlassFish日志抛出这个错误,在SOAP-UI测试后:
Caused by: Exception [EclipseLink-0] (Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd): org.eclipse.persistence.exceptions.JPQLException
Exception Description: Syntax error parsing [select * from ViVertragDl c where c.id = 51].
[28, 28] A select statement must have a FROM clause.
[7, 7] The left expression is missing from the arithmetic expression.
[9, 27] The right expression is not an arithmetic expression.
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.buildException(HermesParser.java:155)
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.validate(HermesParser.java:334)
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.populateQueryImp(HermesParser.java:278)
at org.eclipse.persistence.internal.jpa.jpql.HermesParser.buildQuery(HermesParser.java:163)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.buildEJBQLDatabaseQuery(EJBQueryImpl.java:142)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.buildEJBQLDatabaseQuery(EJBQueryImpl.java:116)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.<init>(EJBQueryImpl.java:102)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.<init>(EJBQueryImpl.java:86)
at org.eclipse.persistence.internal.jpa.EntityManagerImpl.createQuery(EntityManagerImpl.java:1603)
... 91 more
它只是说“select语句必须有FROM子句“,但在我看来有一个。
好吧,我自己固定它。应该有“c”而不是“*”Wildmarks似乎不能在JPQL – TheRealHypo
中工作“似乎不工作”? JPQL有一个定义的语法。这不是猜测。 www.datanucleus.org/products/accessplatform_4_2/jpa/jpql.html –