我有以下几点:如何将元素追加到String [] []?
String[][] content = {
{"c","d", "2"},
{"e","f", "3"},
{"g","h", "4"},
{"i","j", "5"}} ;
我能做些什么,以添加一些元素×3到已经存在的呢?
我有以下几点:如何将元素追加到String [] []?
String[][] content = {
{"c","d", "2"},
{"e","f", "3"},
{"g","h", "4"},
{"i","j", "5"}} ;
我能做些什么,以添加一些元素×3到已经存在的呢?
public static void main(String[] args) {
String[][] content = {
{"c","d", "2"},
{"e","f", "3"},
{"g","h", "4"},
{"i","j", "5"}};
String[][] newContent = {{"p","a", "3"}};
System.out.println(Arrays.deepToString(append(content, newContent)));
}
public static String[][] append(String[][] a, String[][] b) {
String[][] result = new String[a.length + b.length][];
System.arraycopy(a, 0, result, 0, a.length);
System.arraycopy(b, 0, result, a.length, b.length);
return result;
}
输出
[[c, d, 2], [e, f, 3], [g, h, 4], [i, j, 5], [p, a, 3]]
另一输入
String[][] content = {
{"c","d", "2"},
{"S","2"},
{"i","j", "5"},{"p","1"}};
String[][] newContent = {{"p","a", "3"},{"k","3"}};
输出
[[c, d, 2], [S, 2], [i, j, 5], [p, 1], [p, a, 3], [k, 3]]
@uksz如果我的回答是有用的,那么请upvote并接受我的答案,提前致谢! –
这很麻烦,涉及创建整个数组的一个副本,因此不是经常做的事:
String[][] content = {
{"c","d", "2"},
{"e","f", "3"},
{"g","h", "4"},
{"i","j", "5"}};
content = Arrays.copyOf(content, content.length + 1);
content[content.length - 1] = new String[] { "k", "l", "6" };
但是你可以用列表的工作:
List<String[]> list = new ArrayList<>();
Collections.addAll(list, content);
list.add(new String[] { "k", "l", "6" });
有了这样操作:
String[] row = list.remove(2);
list.get(1)[3]; // Getting
list.add(0, row); // Adding at an index
你好,先生,请检查我的答案,这是非常有序和甜蜜:) –
@ParthSolanki不错;你不需要像进口和类的东西;) –
好吧,先生,谢谢你的建议,我会更新我的答案。 –
二维数组是固定长度的。你不能追加元素给他们。最好的选择(与二维数组保持一致)是创建一个更大尺寸的新数组,以保存当前值和新值。然后将所有值添加到它。 –
Yash Capoor是对的。如果这种方法太麻烦了,你可能会更好地切换到'ArrayList'。 –
Daneel
@uksz请检查我的答案 –