查找24小时格式的时差

Question

如何获得24小时格式的两个值的时差？

例如

var time1 = 22:30:00, 
    time2 = 06:30:00; 

差异应是08:00:00

Answer 1

如果你想在C＃中DIFF功能;

DateTime oldDate= "06/01/2014 12:00:00 AM"; 
TimeSpan timeDiff = DateTime.Now - oldDate; 

int diff =Convert.ToInt32(timeDiff.TotalHours); 

如果你想在JavaScript中它是一个脚本块应该帮助你;

function diffDateTime(startDT, endDT) { 

     if (typeof startDT == 'string' && startDT.match(/^[0-9]{1,2}:[0-9]{1,2}:[0-9]{1,2}[amp ]{0,3}$/i)) { 
      startDT = startDT.match(/^[0-9]{1,2}:[0-9]{1,2}:[0-9]{1,2}/); 
      startDT = startDT.toString().split(':'); 
      var obstartDT = new Date(); 
      obstartDT.setHours(startDT[0]); 
      obstartDT.setMinutes(startDT[1]); 
      obstartDT.setSeconds(startDT[2]); 
     } 
     else if (typeof startDT == 'string' && startDT.match(/^now$/i)) var obstartDT = new Date(); 
     else if (typeof startDT == 'string' && startDT.match(/^tomorrow$/i)) { 
      var obstartDT = new Date(); 
      obstartDT.setHours(24); 
      obstartDT.setMinutes(0); 
      obstartDT.setSeconds(1); 
     } 
     else var obstartDT = new Date(startDT); 

     if (typeof endDT == 'string' && endDT.match(/^[0-9]{1,2}:[0-9]{1,2}:[0-9]{1,2}[amp ]{0,3}$/i)) { 
      endDT = endDT.match(/^[0-9]{1,2}:[0-9]{1,2}:[0-9]{1,2}/); 
      endDT = endDT.toString().split(':'); 
      var obendDT = new Date(); 
      obendDT.setHours(endDT[0]); 
      obendDT.setMinutes(endDT[1]); 
      obendDT.setSeconds(endDT[2]); 
     } 
     else if (typeof endDT == 'string' && endDT.match(/^now$/i)) var obendDT = new Date(); 
     else if (typeof endDT == 'string' && endDT.match(/^tomorrow$/i)) { 
      var obendDT = new Date(); 
      obendDT.setHours(24); 
      obendDT.setMinutes(0); 
      obendDT.setSeconds(1); 
     } 
     else var obendDT = new Date(endDT); 
     var secondsDiff = (obendDT.getTime() - obstartDT.getTime()) > 0 ? (obendDT.getTime() - obstartDT.getTime())/1000 : (86400000 + obendDT.getTime() - obstartDT.getTime())/1000; 
     secondsDiff = Math.abs(Math.floor(secondsDiff)); 

     var oDiff = {};  // object that will store data returned by this function 

     oDiff.days = Math.floor(secondsDiff/86400); 
     oDiff.totalhours = Math.floor(secondsDiff/3600);  // total number of hours in difference 
     oDiff.totalmin = Math.floor(secondsDiff/60);  // total number of minutes in difference 
     oDiff.totalsec = secondsDiff;  // total number of seconds in difference 

     secondsDiff -= oDiff.days * 86400; 
     oDiff.hours = Math.floor(secondsDiff/3600);  // number of hours after days 

     secondsDiff -= oDiff.hours * 3600; 
     oDiff.minutes = Math.floor(secondsDiff/60);  // number of minutes after hours 

     secondsDiff -= oDiff.minutes * 60; 
     oDiff.seconds = Math.floor(secondsDiff);  // number of seconds after minutes 

     return oDiff; 
    } 

usage;

var objDiff = diffDateTime('06/01/2014 12:00:00 AM', 'now'); 
var dtdiff = objDiff.days + ' days, ' + objDiff.hours + ' hours, ' + objDiff.minutes + ' minutes, ' + objDiff.seconds + ' seconds'; 

重要：你要记住，DateTime格式必须是EN-US格式DD/MM/YYYY HH：MM：SS。

Answer 2

我建议你应该使用jquery date.js库，那么你可以使用它的时间跨度类象下面这样：

var future = Date.parseExact("22:30:00", "hh:mm:ss"); 

var past = Date.parseExact("06:30:00", "hh:mm:ss"); 

var span = new TimeSpan(future - now); 

和你的时间差异如下：

span.getHours() + ":" span.getMinutes() + ":" span.getSeconds() 

Answer 3

你是多少最好用全日期对象来做这种类型的数学运算，否则你必须对时间值进行猜测，例如，如果结束时间小于开始时间，则必须在第二天。

以下包括一对帮助函数和一个主要函数来获得差异。

// Convert h:m:s to seconds 
function hmsToSecs(s) { 
    var b = s.split(':'); 
    return b[0]*3.6e3 + b[1]*60 + +b[2]; 
} 

// Convert seconds to hh:mm:ss 
function secsToHMS(n) { 
    function z(n){return (n<10? '0':'') + n;} 
    var sign = n < 0? '-' : ''; 
    n = Math.abs(n); 
    return sign + z(n/3.6e3|0) + ':' + z(n%3.6e3/60|0) + ':' + z(n%60); 
} 

// Calculate time difference between two times 
// start and finish in hh:mm:ss 
// If finish is less than start, assume it's the following day 
function timeDiff(start, finish) { 
    var s = hmsToSecs(start); 
    var f = hmsToSecs(finish); 

    // If finish is less than start, assume is next day 
    // so add 24hr worth of seconds 
    if (f < s) f += 8.64e4; 

    return secsToHMS(f - s); 
} 

console.log(timeDiff('22:30:00','06:30:00')); // 08:00:00 
console.log(timeDiff('06:30:00','22:30:00')); // 16:00:00 

使用完整日期的对象，你可以这样做：

var start = new Date(2014,5,5,22,30); // 22:30:00 on 5 June 2014 
var finish = new Date(2014,5,6,6,30); // 06:30:00 on 6 June 2014 

// Subtract dates to get difference in ms, convert to seconds and format 
console.log(secsToHMS((finish - start)/1000)); // 08:00:00 
console.log(secsToHMS((start - finish)/1000)); // -08:00:00