#include <iostream>
#include <string.h>
using namespace std;
class withCC
{
public:
withCC() {}
withCC(const withCC&) {
cout<<"withCC(withCC&)"<<endl;
}
};
class woCC
{
enum {bsz = 100};
char buf[bsz];
public:
woCC(const char* msg = 0) {
memset(buf, 0, bsz);
if(msg) strncpy(buf, msg, bsz);
}
void print(const char* msg = 0)const {
if(msg) cout<<msg<<":";
cout<<buf<<endl;
}
};
class composite
{
withCC WITHCC;
woCC WOCC;
public:
composite() : WOCC("composite()") {}
void print(const char* msg = 0) {
cout<<"in composite:"<<endl;
WOCC.print(msg);
}
};
int main()
{
composite c;
c.print("contents of c");
cout<<"calling composite copy-constructor"<<endl;
composite c2 = c;
c2.print("contents of c2");
}
运行结果低于:为什么这个复制构造函数在程序中被调用?
$ ./a.out
in composite:
contents of c:composite()
calling composite copy-constructor
withCC(withCC&)
in composite:
contents of c2:composite()
而且我不明白为什么withCC(withCC&)
是作为输出的一部分。我猜composite c2 = c;
会导致执行复制构造函数。但是,如下所示,WITHCC
是class composite
的一部分,为什么它会被调用来处理这个拷贝构造函数?谢谢!
构造? –
@AshRj:我不认为这是相当重复的:这里用户想知道复制构造函数w.r.t的行为。组成,而不是继承。 –
@MFFooz我的错误。已移除链接。 – asheeshr