查找数组中不同数字的方法及其频率

Question

帮我找到这段代码中的错误，我不明白为什么它不起作用。我想显示数组中的所有唯一数字，以及它们的频率（它们发生的次数）。

package myProj; 

import java.util.Scanner; 

public class Freq { 

    static boolean isRepeated(int[] temp,int zz){ 
     int flag=0; 
     int l=java.util.Arrays.asList(temp).indexOf(zz); 
     for(int p=0;p<l;p++){ 
      if(temp[p]==zz){ 
       flag=flag+1; 
      } 
     } 
     if(flag==0){ 
      return false; 
      } 
     else{ 
      return true; 
      } 
    } 

    public static void main(String[] args) { 
     Scanner sc=new Scanner(System.in); 
     System.out.println("enter the no of array elements"); 
     int numOfNumbers = sc.nextInt(); 

     int arrayOfNumbers[] = new int[numOfNumbers]; 
     for (int i = 0; i < numOfNumbers; i++) { 
      System.out.print("Enter the number:"); 
      arrayOfNumbers[i] =sc.nextInt(); 
     } 

     for(int i = 0; i<numOfNumbers; i++){ 
      int z=arrayOfNumbers[i]; 
      if(!(isRepeated(arrayOfNumbers,z))){ 
       int count=0; 
       for(int j=0;j<numOfNumbers;j++){ 

        if(arrayOfNumbers[j]==arrayOfNumbers[i]){ 
         count=count+1; 
        } 
        else{ 
         continue; 
        } 
       } 
       System.out.println("Frequency of "+arrayOfNumbers[i]+"is"+count); 
      } 
      else{ 
       continue; 
      } 
     } 
    } 
} 

实施例预期输出频率的[2，20，11，10，5，14，47，23，20，12，11，10]

• 2:1频率20的：2频率的11：2频率 10：频率的5 2：1频率14：频率的47 1：1 频率的23：频率的1 12：1

请帮助纠正我的代码而不是提出新的逻辑。

Answer 1

你可以使它更容易：

public class Freq { 

    public static void main(String[] args) { 
     Scanner sc = new Scanner(System.in); 
     System.out.println("enter the no of array elements"); 
     int numOfNumbers = sc.nextInt(); 

     Integer[] arrayOfNumbers = new Integer[numOfNumbers]; 
     for (int i = 0; i < numOfNumbers; i++) { 
      System.out.print("Enter the number:"); 
      arrayOfNumbers[i] = sc.nextInt(); 
     } 

     // to remember for what numbers we already count freq 
     List<Integer> tmpList = new ArrayList<>(numOfNumbers); 

     for (Integer number : arrayOfNumbers) { 
      if (!tmpList.contains(number)) { 
       tmpList.add(number); 
       System.out.println("Frequency of " + number + " is " + Collections.frequency(Arrays.asList(arrayOfNumbers), number)); 
      } 
     } 
    } 
}