延迟循环并暂停它

我有这段代码。在我的代码中，我需要延迟操作启动（它工作正常），但在操作中我需要检查InitInProcess（）值。如果为假，则断开循环，如果为真，则等待500ms并再次检查。但结果我得到的检查灵巧，而不是每隔500毫秒。延迟循环并暂停它

Handler myHandler = new Handler(); 
     myHandler.postDelayed(new Runnable() { 

      @Override 
      public void run() { 

       int test = 0; 
       while (test!=20) 
       { 
        if (InitInProcess()) 
         break; 

        try { 
         Thread.sleep(500); 
        } catch (InterruptedException e) { 

         e.printStackTrace(); 
        } 

        Log.d("MyApp", ""+test); 


        test++; 
       } 

      } 
     }, 3000);

日志（看时间）：

02-27 12:48:41.707: D/MyApp(10082): 0 
    02-27 12:48:42.212: D/MyApp(10082): 1 
    02-27 12:48:42.712: D/MyApp(10082): 2 
    02-27 12:48:43.267: D/MyApp(10082): 3 
    02-27 12:48:43.767: D/MyApp(10082): 4 
    02-27 12:48:44.272: D/MyApp(10082): 5 
    02-27 12:48:44.772: D/MyApp(10082): 6 
    02-27 12:48:45.277: D/MyApp(10082): 7 
    02-27 12:48:45.777: D/MyApp(10082): 8 
    02-27 12:48:46.277: D/MyApp(10082): 9 
    02-27 12:48:46.777: D/MyApp(10082): 10 
    02-27 12:48:47.277: D/MyApp(10082): 11 
    02-27 12:48:47.772: D/MyApp(10082): 12 
    02-27 12:48:48.277: D/MyApp(10082): 13 
    02-27 12:48:48.777: D/MyApp(10082): 14 
    02-27 12:48:49.277: D/MyApp(10082): 15 
    02-27 12:48:49.777: D/MyApp(10082): 16 
    02-27 12:48:50.277: D/MyApp(10082): 17 
    02-27 12:48:50.782: D/MyApp(10082): 18 
    02-27 12:48:51.277: D/MyApp(10082): 19

来源

2014-02-27 Dim

我错了???这些是500毫秒的步骤。 –

500ms是0.5秒，全部在12:48 – Dim

哦....抱歉，我因为疲倦而犯了愚蠢的错误，这是500ms，我看了一下分钟。新人的东西！ – Dim

private static final long RETRY_DELAY = 500; 
private static final int RETRY_COUNT = 10; 
private Handler myHandler = new Handler() { 
     @Override 
     public void handleMessage(android.os.Message msg) { 
      if (!InitInProcess() && msg.what>0) { 
       myHandler.sendEmptyMessageDelayed(msg.what-1, RETRY_DELAY); 
      } 
     } 
    }; 

    myHandler.sendEmptyMessageDelayed(RETRY_COUNT, RETRY_DELAY);

来源

2014-02-27 11:27:17 Vivart

int test = 0; 
while (test!=20){ 
     if (InitInProcess()) 
      break; 

try { 
    myHandler.postDelayed(new Runnable() { 
        test++; 
Log.d("MyApp", ""+test); 
     },500); 
    } catch (Exception e) { 
     e.printStackTrace(); 
    }

}

来源

2014-02-27 11:09:36

延时500ms在哪里？ – Dim

使用500个3000的地方 –

延迟循环并暂停它

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