MySQL查询选择最大值

Question

我有这两个表：

product 
id | name 
1 | A 
2 | B 

history 
id_product | year | month | percent 
1   | 2014 | 2 | 0 
1   | 2014 | 3 | 20 
1   | 2014 | 4 | 60 

我怎样才能获得最高百分比如果月份是当月或一个月之前，例如：

SELECT * FROM history 
WHERE id_product IN 
    (SELECT id FROM product 
     WHERE id = 1) 
    AND ((year = 2014 AND month = 3) OR 
     (year = 2014 AND month = 2)) 
ORDER BY year DESC, month DESC 

这将输出：20，但它实际上显示0，它总是给我在月前值...任何建议都欢迎...谢谢！

Answer 1

SELECT max(hs.`percent`) as `percent`, hs.id_product, p.name FROM 
(SELECT * 
FROM history 
WHERE ((year = 2014 AND month = 3) OR 
     (year = 2014 AND month = 2)) 
) as hs 
LEFT JOIN `product` as p on p.id=hs.id_product 
GROUP BY hs.id_product 

试试这个。