我有一种方法,必须从用户上传的原始文件中创建一个zip和mat文件。 所以我决定只存储原始文件,然后在异步任务中我想创建其他两个文件。 我读了@Async
注释有两个限制: 1)只有在公共方法 2)@Async
方法必须在不同的对象尊重调用方类。 所以我创建了一个新类,并将其放入我的异步方法中,但它仍然没有工作。 这是调用异步方法的类:@Async Spring注解不起作用
@Service
public class FleetAcquisitionServicesImpl implements FleetAcquisitionServices{
@Autowired
private DatabaseAcquisitionServices databaseAcquisitionServices;
@Autowired
private DatabaseFleetsAndCarsServices databaseFleetsAndCarsServices;
@Autowired
private FleetFolderName fleetFolderName;
private static final int NUMBER_OF_SHEET=4;
@Override
public ArrayList<String> uploadFiles(MultipartFile[] openedFiles, Integer idFleet, Integer idCar, Integer initialKm) throws FileUploadException, FileEmptyException{
ArrayList<String> filesName=new ArrayList<String>();
String fileName=null;
String carPath=null;
for (MultipartFile openedFile:openedFiles){
if (!openedFile.isEmpty()) {
//Copy the file into path specified
fileName = openedFile.getOriginalFilename();
try {
//Get the path where to store the file
Fleet fleet=databaseFleetsAndCarsServices.getFleetById(idFleet);
Car car=databaseFleetsAndCarsServices.getCarById(idCar);
carPath= fleetFolderName.createCarName(fleet, car);
if (FilenameUtils.getExtension(fileName).equals("dat")){
fileName = FilenameUtils.removeExtension(fileName)+"_km"+initialKm;
//write dat file
openedFile.transferTo(new File(carPath +"/"+ fileName+".dat"));
ZipAndMat.createZipAndMat(carPath,fileName);
}else
openedFile.transferTo(new File(carPath +"/"+ fileName));
} catch (Exception e) {
throw new FileUploadException("you failed to upload " + fileName,e);
}
filesName.add(carPath +"/"+ fileName);
} else {
throw new FileEmptyException("your file is empty " + openedFile.getOriginalFilename());
}
}
return filesName;
}
ZipAndMat.createZipAndMat(carPath,fileName)
是异步方法,它是在这里:
package com.model;
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.util.concurrent.Future;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
import org.springframework.scheduling.annotation.Async;
import org.springframework.scheduling.annotation.AsyncResult;
import com.mathworks.toolbox.javabuilder.MWException;
import dataconversion.Converter;
public class ZipAndMat {
@Async
public static Future<String> createZipAndMat(String filePath, String fileName){
try {
Thread.sleep(20000L);
} catch (InterruptedException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
//Open file
Path path = Paths.get(filePath, fileName + ".dat");
try {
//Create zip
byte[] zip = zipBytes(Files.readAllBytes(path),fileName+".dat");
Files.write(Paths.get(filePath +"/"+ fileName+".zip"), zip);
//create mat file
Converter objConv = new Converter();
objConv. dat2MatConversion(filePath +"/", fileName + ".dat", 0.2);
} catch (IOException e) {
return new AsyncResult<String>("Zip not created");
} catch (MWException e){
return new AsyncResult<String>("Mat not created");
}
return new AsyncResult<String>("Zip created");
}
/**
* Convert a file into zip file keeping the same name
* @param filename
* @param input
* @return
* @throws IOException
*/
private static byte[] zipBytes(byte[] input, String filename) throws IOException {
ByteArrayOutputStream baos = new ByteArrayOutputStream();
ZipOutputStream zos = new ZipOutputStream(baos);
ZipEntry entry = new ZipEntry(filename);
entry.setSize(input.length);
zos.putNextEntry(entry);
zos.write(input);
zos.closeEntry();
zos.close();
return baos.toByteArray();
}
}
我试图TU但@EnableAsync
两个主叫类的confiuration类,但它不起作用。 我的代码有什么问题?静态方法? 感谢
我对弹簧一无所知,但通过https://spring.io/guides/gs/async-method/ show您需要在'@Service'上调用该方法 - 它们的示例使用非静态方法。否则,你只是调用'createZipAndMat'作为普通的旧静态方法 - 不存在异步性的可能性。你确定你的2个要求是足够的吗? –
ZipandMat应该是一个春天的豆子.. – ArunM
我试过添加@Component,但它不起作用 – luca