我已经使用Django创建了一个员工管理系统。我已经完成了一个过滤方法,它基于从下拉菜单和文本输入中选择的一个选项。过滤工作正常。在第一页上,它给出了可以按升序和降序显示的整个员工名单。在同一页面上给出了过滤方法。过滤的数据显示在另一页中。现在我想在过滤的数据页面上放一个按钮,点击该按钮以升序/降序显示数据。我已经编写了一个单独的函数,用于在完整员工列表的视图中升序和降序。它如何用于此功能。我会在这里粘贴我的代码。由于我是django编程新手,请帮助我找到解决方案。
我已经给出了2个单独的图像升序和降序。我想这样:点击1图像列表中的升序;并点击其他图片按降序排列。在django中按升序/降序对已过滤列表进行排序
筛选()
def filter(request):
val3=''
if request.GET.has_key('choices'):
val2=request.GET.get('choices')
if request.GET.has_key('textField'):
val3=request.GET.get('textField')
if request.POST:
val2=request.POST.get('choices')
val3=request.POST.get('textField')
if val2=='Designation':
newData = EmployeeDetails.objects.filter(designation=val3)
flag=True
elif val2=='Name':
newData = EmployeeDetails.objects.filter(userName__icontains=val3)
flag=True
elif val2=='EmployeeID':
newData = EmployeeDetails.objects.filter(employeeID=val3)
flag=True
elif val2=='Project':
newData = EmployeeDetails.objects.filter(project=val3)
flag=True
elif val2=='DateOfJoin':
newData = EmployeeDetails.objects.filter(dateOfJoin=val3)
flag=True
else:
return HttpResponseRedirect('/employeeList/')
#tableList = EmployeeDetails.objects.all()
paginator = Paginator(newData, 10)
try:
page = int(request.GET.get('page', '1'))
except ValueError:
page = 1
try:
contacts = paginator.page(page)
except (EmptyPage, InvalidPage):
contacts = paginator.page(0)
return render_to_response('filter.html',{'newData':newData,'emp_list': contacts,'val2':val2,'val3':val3,'flag':flag})
filter.html
<div>
Employees List
<a STYLE="text-decoration:none" align=center href="http://10.1.0.90:8080/sortAscend/ "> <img src="/static/sort_asc.gif " border="1" height="12" /> </a>
<h4 align="left">
{%for data in newData%}
<a STYLE="text-decoration:none" href ="http://10.1.0.90:8080/singleEmployee/{{data.id}}?choices={{val2}}&textField={{val3}}&flag=1 ">
{{ data.userName}}<br>
{%endfor%}
</h4>
</div>
升降功能
def sortAscend(request):
tableList = EmployeeDetails.objects.all().order_by('userName')
paginator = Paginator(tableList, 12)
try:
page = int(request.GET.get('page', '1'))
except ValueError:
page = 1
try:
contacts = paginator.page(page)
except (EmptyPage, InvalidPage):
contacts = paginator.page(0)
return render_to_response('sortAscend.html', {'emp_list': contacts})
#Method for listing the employees in descending order
def sortDescend(request):
tableList = EmployeeDetails.objects.all().order_by('-userName')
paginator = Paginator(tableList, 12)
try:
page = int(request.GET.get('page', '1'))
except ValueError:
page = 1
try:
contacts = paginator.page(page)
except (EmptyPage, InvalidPage):
contacts = paginator.page(0)
return render_to_response('sortDescend.html', {'emp_list': contacts})
sortAscending.html
{%for emp in emp_list.object_list%}
<tr> <td><a STYLE="text-decoration:none" href ="http://10.1.0.90:8080/singleEmployee/{{emp.id}} "> {{ emp.userName }} </a></td> </tr><td>
{%endfor%}
如果您希望按照即时排序的方式排序表格而不生成新页面,请查看JS。 – KyleWpppd 2011-03-17 11:43:44