2016-05-25 148 views
3

我有一个表单。当用户提交时,这些值应该插入到数据库中。只有一个$ _POST的值没有被插入到数据库中,但是其他$ _POST被正确插入。

如何解决这一问题?

HTML:

<input type="text" name="position" value="<?php echo $_POST['jobTitle']; ?>" id="position" required/> 

PHP代码片段:

$firstName = $middleName = $lastName = $email = $mobile = $resume = $position = $message = $attachment_id = $locations = ""; 

if(isset($_POST['submit'])){ 
    $firstName = isset($_POST['firstName']) ? $_POST['firstName'] : ''; 
    $middleName = isset($_POST['middleName']) ? $_POST['middleName'] : ''; 
    $lastName = isset($_POST['lastName']) ? $_POST['lastName'] : ''; 
    $email = isset($_POST['email']) ? $_POST['email'] : ''; 
    $mobile = isset($_POST['mobile']) ? $_POST['mobile'] : ''; 
    $locations = isset($_POST['locations_list']) ? $_POST['locations_list'] : ''; 
    $position = isset($_POST['jobTitle']) ? $_POST['jobTitle'] : ''; 
    $message = isset($_POST['message']) ? $_POST['message'] : ''; 
     if(! empty($_FILES)){ 
      $file=$_FILES['resumeFile']; 
      $attachment_id = upload_user_file($file); 
     } 

    $sql=$wpdb->query("INSERT INTO resume_databank(submit_time,last_name,first_name,middle_name,mobile_number,email,location,position,message,process_resume,attachment_resume_id) VALUES (now(),'$lastName','$firstName','$middleName','$mobile','$email','$locations','$position','$message','No','$attachment_id')"); 
} 

exit(); 
+1

“$ wpdb”从哪里来? –

+0

'$ wpdb'是wordpress中的一个全局变量 – User014019

+1

您可以调试它:只是回显此 - “INSERT INTO resume_databank(submit_time,last_name,first_name,middle_name,mobile_number,email,location,position,message,process_resume,attachment_resume_id)VALUES (NOW(), '$ lastName的', '$的firstName', '$中间名', '$移动', '$电子邮件', '$位置', '$位置', '$消息', '没有',” $ attachment_id')“'。 –

回答

4

更改这一部分

$position = isset($_POST['jobTitle']) ? $_POST['jobTitle'] : ''; 

$position = isset($_POST['position']) ? $_POST['position'] : ''; 

因为在你的形式。您的字段名称是position$_POST['jobTitle'];只是一个值