<?php
if($_SERVER['REQUEST_METHOD']=='POST'){
$username = $_POST['username'];
$password = $_POST['password'];
$sql = "SELECT * FROM main_member WHERE username='$username' AND password='$password'";
require_once('connect.php');
sql $result = mysqli_query($con,$sql);
$check = mysqli_fetch_array($result);
if(isset($check));
{
echo "success";
}else{
echo "Gagal";
}
mysqli_close($con);
}
?>
它说:解析错误语法错误,意想不到的$结果T_VARIABLE在C:\ XAMPP \ htdocs中\第7行的php \ login.php中,请帮帮我大家好我真的很感激它获取解析/语法错误,无法弄清楚,为什么
为什么之前'$'result' sql'? – Musa
我不知道,我只是从别人的项目复制 –