获取单个记录基于ID

Question

我正在从我的REST API在http://127.0.0.1:8000/api/category/以下回应：

[ 
    { 
     "id": "17442811-3217-4b67-8c2c-c4ab762460d6", 
     "title": "Hair and Beauty" 
    }, 
    { 
     "id": "18a136b5-3dc4-4a98-97b8-9604c9df88a8", 
     "title": "Plumbing" 
    }, 
    { 
     "id": "2f029642-0df0-4ceb-9058-d7485a91bfc6", 
     "title": "Personal Training" 
    } 
] 

如果我想访问，一个记录，我相信我会需要去http://127.0.0.1:8000/api/category/17442811-3217-4b67-8c2c-c4ab762460d6访问：

[ 
    { 
     "id": "17442811-3217-4b67-8c2c-c4ab762460d6", 
     "title": "Hair and Beauty" 
    } 
] 

但是，当我尝试这个，它会返回所有的记录。我该如何解决这个问题？这是到目前为止我的代码：

urls.py

urlpatterns = [ 
    url(r'^category/', views.CategoryList.as_view(), name="category_list"), 
    url(r'^category/?(?P<pk>[^/]+)/$', views.CategoryDetail.as_view(), name="category_detail") 
] 

views.py

class CategoryList(generics.ListAPIView): 
    """ 
    List or create a Category 
    HTTP: GET 
    """ 
    queryset = Category.objects.all() 
    serializer_class = CategorySerializer 


class CategoryDetail(generics.RetrieveUpdateDestroyAPIView): 
    """ 
    List one Category 
    """ 
    serializer_class = CategorySerializer 

serializers.py

class CategorySerializer(serializers.ModelSerializer): 
    """ 
    Class to serialize Category objects 
    """ 
    class Meta: 
     model = Category 
     fields = '__all__' 
     read_only_fields = ('id') 

models.py

class Category(models.Model): 
    """ 
    Category model 
    """ 
    id = models.UUIDField(primary_key=True, default=uuid4, editable=False) 
    title = models.CharField(max_length=255) 

    def __str__(self): 
     return "%s" % (self.title) 

Answer 1

你的第一个正则表达式，r'^category/'，既是一个URL匹配有和没有一个UUID。

你应该在最后固定在那里：

r'^category/$' 

此外/或者，你可以交换的URL定义的顺序，因为Django会采取它匹配的第一个。