2016-10-03 60 views
1

我想用PHP将图像上传到各自的文件夹。共有6个文件夹和2个文件夹都有子文件夹。我创建了一个包含文件夹和子文件夹列表的下拉列表。现在我可以创建缩略图,但无法将原始图像存储在相应的文件夹中。我如何在函数中编写动态路径?如何在图片上传功能中提供动态路径?

我想用下面的动态路径:

$target_folder = "images/website/". $_POST["path"]."/"; 

,但我得到的错误了这条道路。

下面是cwUpload函数的以下代码。

<?php 
function cwUpload($field_name = '', $target_folder = '', $file_name = '', $thumb = FALSE, $thumb_folder = '', $thumb_width = '', $thumb_height = ''){ 
//folder path setup 
$target_path = $target_folder; 
$thumb_path = $thumb_folder; 

//file name setup 
$filename_err = explode(".",$_FILES[$field_name]['name']); 
$filename_err_count = count($filename_err); 
$file_ext = $filename_err[$filename_err_count-1]; 
if($file_name != '') 
{ 
    $fileName = $file_name.'.'.$file_ext; 
} 
else 
{ 
    $fileName = $_FILES[$field_name]['name']; 
} 

//upload image path 
$upload_image = $target_path.basename($fileName); 

//upload image 
if(move_uploaded_file($_FILES[$field_name]['tmp_name'],$upload_image)) 
{ 
    //thumbnail creation 
    if($thumb == TRUE) 
    { 
     $thumbnail = $thumb_path.$fileName; 
     list($width,$height) = getimagesize($upload_image); 
     $thumb_create = imagecreatetruecolor($thumb_width,$thumb_height); 
     switch($file_ext){ 
      case 'jpg': 
       $source = imagecreatefromjpeg($upload_image); 
       break; 
      case 'jpeg': 
       $source = imagecreatefromjpeg($upload_image); 
       break; 
      case 'png': 
       $source = imagecreatefrompng($upload_image); 
       break; 
      case 'gif': 
       $source = imagecreatefromgif($upload_image); 
       break; 
      default: 
       $source = imagecreatefromjpeg($upload_image); 
     } 
     imagecopyresized($thumb_create,$source,0,0,0,0,$thumb_width,$thumb_height,$width,$height); 
     switch($file_ext){ 
      case 'jpg' || 'jpeg': 
       imagejpeg($thumb_create,$thumbnail,100); 
       break; 
      case 'png': 
       imagepng($thumb_create,$thumbnail,100); 
       break; 
      case 'gif': 
       imagegif($thumb_create,$thumbnail,100); 
       break; 
      default: 
       imagejpeg($thumb_create,$thumbnail,100); 
     } 
    } 

    return $fileName; 
} 
else 
{ 
    return false; 
} 
} 
    if(!empty($_FILES['fileToUpload']['name'])){ 

//call thumbnail creation function and store thumbnail name 
$upload_img = cwUpload('fileToUpload','images/','',TRUE,'images/thumbs/','200','160'); 

//full path of the thumbnail image 
$thumb_src = 'images/thumbs/'.$upload_img; 

//set success and error messages 
$message = $upload_img?"<span style='color:#008000;'>Image thumbnail have been created successfully.</span>":"<span style='color:#F00000;'>Some error occurred, please try again.</span>"; 

    }else{  
    `//if form is not submitted, below variable should be blank 
    $thumb_src = ''; 
     $message = ''; 
    } 
    ?> 
+0

之前只需创建一个目标文件夹,请检查相应的文件夹 – Elby

+0

的权限,请添加一些明智的代码缩进 – RiggsFolly

+0

@Elby我检查的权限。当我尝试直接上传图片而不创建缩略图时,我可以添加图片。我只需要$ target_folder部分中的一个正确路径 – HebleV

回答

0

您需要创建一个动态目录来做到这一点。 一个 move_uploaded_file

mkdir("images/website/'. $_POST[path].'"); 
$target_folder = "images/website/". $_POST['path']."/"; 
+0

创建了Asusual缩略图,但出现此错误Warning:mkdir():Invalid argument in – HebleV

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