如何字符串比较选项值

php
mysql

2010-04-20 47 views 0 likes

<tr> 
<td width="30" height="35"><font size="3">*List:</td> 
<td width="30"><input name="specific" type="text" id="specific" maxlength="25" value=""> 
</td> 

<td><font size="3">*By:</td> 
<td> 
    <select name="general" id="general"> 
     <font size="3"> 
     <option value="YEAR">Year</option> 
     <option value="ADDRESS">Address</option> 


    </select></td></td> 
    </tr>

而且我想有这样的形式作用：

if ('{$_POST["ADDRESS"]}'="ADDRESS")

哪样比较html表单中的选项中的值是否与单词“Address”匹配。如果匹配然后它会执行这个查询：

$saddress= mysql_real_escape_string($_POST['specific']);<--this is the input form where the user will put the specific address to search. 

mysql_query("SELECT * FROM student WHERE ADDRESS='$saddress'");

请我需要帮助在这里，我认为它错了：

if ('{$_POST["ADDRESS"]}'="ADDRESS")

来源

2010-04-20 user225269

回答

if($_POST['general'] == 'ADDRESS')

来源

2010-04-20 02:08:26 Puaka

谢谢，你是一个生命的救星。 – user225269 2010-04-20 02:58:43

$test=strcmp($_POST['general'],"ADDRESS"); 
if($test==0) 
{ 
    //Here you can write your operations. 
}

来源

2010-04-20 03:34:44

如何字符串比较选项值

回答

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