我正在编写一个程序,用于查找最多8个字符的单词/短语是否是回文。不管我输入什么东西,即使它是一个回文,我的程序都会打印我的其他语句。我检查并确保我写的代码实际上是反向输入并输入。所以我不太确定问题是什么。为什么我的if语句不能正常工作?
import java.util.Scanner;
public class hw5 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String word, newWord;
int lengthOfWord;
char lc;//last character
System.out.print("Enter word/phrase of 8 characters or less: ");
word = in.nextLine();
word = word.toLowerCase();
newWord = word;
lengthOfWord = word.length();
lc = word.charAt(lengthOfWord -1);
lc = word.charAt(lengthOfWord -1);
if (word.length() == 2)
newWord = lc+word.substring(0,1);
else if (word.length() == 3)
newWord = lc+word.substring(1,2)+word.substring(0,1);
else if (word.length() == 4)
newWord = lc+word.substring(2,3)+word.substring(1,2)+word.substring(0,1);
else if (word.length() == 5)
newWord = lc+word.substring(3,4)+word.substring(2,3)+word.substring(1,2)+word.substring(0,1);
else if (word.length() == 6)
newWord = lc+word.substring(4,5)+word.substring(3,4)+word.substring(2,3)+word.substring(1,2)+word.substring(0,1);
else if (word.length() == 7)
newWord = lc+word.substring(5,6)+word.substring(4,5)+word.substring(3,4)+word.substring(2,3)+word.substring(1,2)+word.substring(0,1);
else if (word.length() == 8)
newWord = lc+word.substring(6,7)+word.substring(5,6)+word.substring(4,5)+word.substring(3,4)+word.substring(2,3)+word.substring(1,2)+word.substring(0,1);
else
newWord = "error, not enough or too many characters";
if (newWord == word)
System.out.println("it is a palindrome");
else
System.out.println("it is not a palindrome");
System.out.println(newWord);
使用'String'的'equals'方法来比较两个字符串值,而不是''==操作符,它决定了两个引用是否指向同一个对象。 – rgettman