我目前正在尝试检查元素是否为列表的一部分,如果是大小写则返回1,否则返回0。测试元素是否在列表中并返回0或1
我一直在做这个循环,但由于矩阵将会非常大(这里只提供一个简单的例子),我想知道是否有一种有效的方法来做到这一点。
rm(list=ls()) # clear memory
names <- c("a","b","c","d","e","f","g","h","i","j","k50","l50","m50","n50","o50")
proba <- c(1,1,1,1,1,1,1,1,1,1,0.5,0.5,0.5,0.5,0.5)
T1_temp <- sample(names,4,prob=proba)
# Loop to check which element of T1_temp is included in names
T1 <- c()
for (i in 1:length(names)){
if (is.element(names[i],T1_temp)){T1[i]=1}
else{T1[i]=0}
}
,结果
[1] 0 1 0 0 1 1 0 0 1 0 0 0 0 0 0
@Donkey香港感谢您重塑我的问题,并感谢JOGO FO提示 – richpiana