从SQL结果汇总结果

Question

我想汇总一些结果，但我没有任何运气。下面是我使用的SQL与实际输出：它生产这个数据

SQL语句：

SELECT 
    i.inventory_item_id, 
    i.organization_id, 
    sum(primary_transaction_quantity) as on_hand_qty 
FROM mtl_onhand_quantities_detail oqd, mtl_system_items_b i 
WHERE oqd.inventory_item_id = i.inventory_item_id 
    AND oqd.inventory_item_id = 117567 -- just used to restrict results for this example 
    AND i.organization_id = :p_organization_id 
    AND oqd.organization_id = i.organization_id 
GROUP BY i.inventory_item_id, i.organization_id, primary_transaction_quantity 


INVENTORY_ITEM_ID,ORGANIZATION_ID,ON_HAND_QTY 
117567,7651,2 
117567,7651,1 

我需要什么返回：

INVENTORY_ITEM_ID,ORGANIZATION_ID,ON_HAND_QTY 
117567,7651,3 

基本上，它需要总结的on_hand_qty并且只返回一个结果行，如果inventory_item_id和organization_id是相同的。任何帮助是极大的赞赏！从组

Answer 1

删除primary_transaction_quantity by子句

Answer 2

好了，让你有主要的问题是，你在你的GROUP BY所以您的查询应该是这样的包含您的累计声明。

SELECT 
    i.inventory_item_id, 
    i.organization_id, 
    sum(primary_transaction_quantity) as on_hand_qty 
FROM mtl_onhand_quantities_detail oqd, mtl_system_items_b i 
WHERE oqd.inventory_item_id = i.inventory_item_id 
    AND oqd.inventory_item_id = 117567 -- just used to restrict results for this example 
    AND i.organization_id = :p_organization_id 
    AND oqd.organization_id = i.organization_id 
GROUP BY i.inventory_item_id, i.organization_id 

不知道，如果你通过对谷歌你应该找到很多解释它是如何工作的查找组您所使用但什么DBMS。

现在让我们继续下一个问题。您正在使用pre ansi-92连接语法。这是bad。

你的代码应该看起来像这样。

SELECT 
    i.inventory_item_id, 
    i.organization_id, 
    sum(primary_transaction_quantity) as on_hand_qty 
FROM mtl_onhand_quantities_detail oqd 
INNER JOIN mtl_system_items_b i 
    ON oqd.inventory_item_id = i.inventory_item_id 
    AND oqd.organization_id = i.organization_id 
    AND i.organization_id = :p_organization_id --Added back the function now that I know it isn't a typo 
WHERE 
    oqd.inventory_item_id = 117567 -- just used to restrict results for this example 
GROUP BY i.inventory_item_id, i.organization_id