C程序我想知道是否有简化我的dayofyear计划吗？

Question

我是C新手，我编写了这个C程序，它让用户输入一年中的某一天，作为回报，程序将输出月份以及月份中的哪一天。该程序运行良好，但我想现在简化程序。我知道我需要一个循环，但我不知道如何去做。这里是关于C标准库<time.h>头，尤其是ctime()和asctime()阅读了程序

#include <stdio.h> 

void SplitDate(int dayofyear, int year, int *month, int *day); 

int main() { 
int month[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; 
int year, dayofyear, *day; 

printf("Enter the day of the year: "); 
scanf("%d", &dayofyear); 
printf("Enter the year: "); 
scanf("%d", &year); 
printf("Day %d of year %d falls on:\n ",dayofyear, year); 

SplitDate(dayofyear, year, month, day); 

} 

void SplitDate(int dayofyear, int year, int *month, int *day) 
{ 
if(dayofyear >=1 && dayofyear <= 31) 
    { 
     printf("month = 1 day = %d\n",dayofyear); 
    } 
    else if(dayofyear >=32 && dayofyear <= 59) 
    { 
     printf("month = 2 day = %d\n", dayofyear - 31); 
    } 
    else if(dayofyear >=60 && dayofyear <=90) 
    { 
     printf("month = 3 day = %d\n", dayofyear - 59); 
    } 
    else if(dayofyear >=91 && dayofyear <=120) 
    { 
    printf("month = 4 day = %d\n", dayofyear - 90); 
    } 
    else if(dayofyear >=121 && dayofyear <=151) 
    { 
    printf("month = 5 day = %d\n", dayofyear - 120); 
    } 
    else if(dayofyear >=151 && dayofyear <=180) 
    { 
    printf("month = 6 day = %d\n", dayofyear - 150); 
    } 
    else if(dayofyear >=181 && dayofyear <=211) 
    { 
    printf("month = 7 day = %d\n", dayofyear - 180); 
    } 
    else if(dayofyear >=212 && dayofyear <=242) 
    { 
    printf("month = 8 day = %d\n", dayofyear - 211); 
    } 
    else if(dayofyear >=243 && dayofyear <=272) 
    { 
    printf("month = 9 day = %d\n", dayofyear - 242); 
    } 
    else if(dayofyear >=273 && dayofyear <=303) 
    { 
    printf("month = 10 day = %d\n", dayofyear -272); 
    } 
    else if(dayofyear >=304 && dayofyear <=333) 
    { 
    printf("month = 11 day = %d\n", dayofyear - 303); 
    } 
    else if(dayofyear >=334 && dayofyear <=364) 
    { 
    printf("month = 12 day = %d\n", dayofyear - 333); 
    } 
} 

Answer 1

void SplitDate(int dayofyear, int year, int *month, int *day){ 
    static int months[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; 
    //months[2] : Requires a correction of leap year 
    int i; 
    for(i=1;i<=12;++i){ 
     if(dayofyear > months[i]){ 
      dayofyear -= months[i]; 
     } else { 
      printf("month = %d\t day = %d\n", i, dayofyear); 
      break; 
     } 
    } 
} 

Answer 2

。了解如何使用它们。