我有一个登录脚本显示,与字段的表,这里需要的一个是“阿凡达”(VARCHAR(255)& defaul项是一个图像链接)链接无法从DB
代码查看个人资料:
<div align="center"><img src="<?php echo $_GET['avatar']; ?>" width="250" height="250" /></div>
代码会话:
function set_session($username, $password) {
$query = $this->query("SELECT * FROM ".DBTBLE." WHERE username='$username' AND password='$password'");
ini_set("session.gc_maxlifetime", Session_Lifetime);
session_start();
$_SESSION['first_name'] = $query['result']['first_name'];
$_SESSION['last_name'] = $query['result']['last_name'];
$_SESSION['email_address'] = $query['result']['email_address'];
$_SESSION['username'] = $query['result']['username'];
$_SESSION['info'] = $query['result']['info'];
$_SESSION['user_level'] = $query['result']['user_level'];
$_SESSION['password'] = $query['result']['password'];
$_SESSION['avatar'] = $query['result']['avatar'];
}
有添加头像没有特色,所以我在表单中添加的节目<div>
功能,创建一个科拉姆n在名为头像的数据库中,并添加了$_SESSION['avatar'] = $query['result']['avatar']
,但默认图像不显示,我哪里出错了?除了头像之外,全部都已经显示。
避免保存在sessison密码.. – Dinesh 2013-05-12 10:46:16