试试这个:
String[] columnDetail = column.split("\t", -1);
阅读String.split(java.lang.String, int)的Javadoc有关split函数的极限参数说明:
split
public String[] split(String regex, int limit)
Splits this string around matches of the given regular expression.
The array returned by this method contains each substring of this string that is terminated by another substring that matches the given expression or is terminated by the end of the string. The substrings in the array are in the order in which they occur in this string. If the expression does not match any part of the input then the resulting array has just one element, namely this string.
The limit parameter controls the number of times the pattern is applied and therefore affects the length of the resulting array. If the limit n is greater than zero then the pattern will be applied at most n - 1 times, the array's length will be no greater than n, and the array's last entry will contain all input beyond the last matched delimiter. If n is non-positive then the pattern will be applied as many times as possible and the array can have any length. If n is zero then the pattern will be applied as many times as possible, the array can have any length, and trailing empty strings will be discarded.
The string "boo:and:foo", for example, yields the following results with these parameters:
Regex Limit Result
: 2 { "boo", "and:foo" }
: 5 { "boo", "and", "foo" }
: -2 { "boo", "and", "foo" }
o 5 { "b", "", ":and:f", "", "" }
o -2 { "b", "", ":and:f", "", "" }
o 0 { "b", "", ":and:f" }
当最后几字段(我的客人,这是你的情况)缺失,你会得到这样的列:
field1\tfield2\tfield3\t\t
如果没有限制被设定为分割()时,下限为0,这将导致对“后空字符串将被丢弃”。所以你只能得到3个字段,{“field1”,“field2”,“field3”}。
当limit设置为-1时,非正值,尾随空字符串不会被丢弃。所以你可以得到5个字段,最后两个字符串为空字符串,{“field1”,“field2”,“field3”,“”,“”}。
所以'字段1 \ tfield2 \ t \ tfield4'给你FIELD1,FIELD2,字段4而不是字段1,字段2,[空]字段4? – 2009-10-28 08:08:46
http://stackoverflow.com/questions/1630092/token-parsing-in-java/1630110重复?当你不明白答案并且复制代码时,会发生这种情况。 – 2009-10-28 08:10:21
你不需要分配一个新的字符串数组。无论如何,'String.split'会分配一个新的。 – Joey 2009-10-28 08:10:47