验证以逗号分隔的十进制值字符char char

Question

我有一个包含货币值的字符串。
我必须从字符串中逐个字符地读取字符，函数必须返回result = 0，以获得val的所有值。

例：string = "You Score is MX var."
哪里var可具有这些值的任何

[14 , 14.98 , 114 , 114.98 , 1116 , 1,116 , 1116.78 , 1,116.18 , 11,12,123 , 1,12,123.89 ... and so on...] 

MY CODE

def evaluate(): 
    result , count = 0 , 0 
    dot , comma = False , False 
    while (index_of_String < Len_of_string): 
     ch = string[index_of_String]   
     if (ch == '.'): 
      if (dot == True): 
       break ;     
      dot = True    
     elif (ch == ','): 
      if (dot == True): 
       break    
      comma = True    
     elif not (ch >= '0' and ch <= '9'): 
      if not (ch == ' ' or ch == ','):     
       result = -1    
      break 
     else: 
      if (dot == False): 
       count += 1 
     print ("Char %c" % ch) 
     index_of_String += 1   

    print ("count of numeric digits %d" % count) 
    if (result == 0): 
     if dot == False: 
      result = -1 
     if comma == False: 
      if (count > 3): 
       result = -1 

    return (result, index_of_String) 

所需的输出

string = "You Score is MX 14." 
result = 0 

string = "You Score is MX 14.89." 
result = 0 

string = "You Score is MX 1114.89." 
result = 0 

string = "You Score is MX 1,114.89." 
result = 0 

string = "You Score is MX 11,,,14.89." 
result = -1 (fail) 

string = "You Score is MX 11.14.89." 
result = -1 (fail) 

string = "You Score is MX 1,114.89." 
result = 0 

string = "You Score is MX 1,14.89." 
result = -1 (fail) 

string = "You Score is MX 1,11,114.89." 
result = 0 

我需要做些什么修改才能使我的代码适用于所有这些情况。
任何帮助修改？

Answer 1

如果烧焦成炭不是那么一个要求：

def evaluate(string, values): 
    for word in string.rstrip('.').split(): 
     if word in values: 
      return False 
    return True 

测试：

>>> values = map(str, [14 , 14.98 , 114 , 114.98 , 1116]) 
['14', '14.98', '114', '114.98', '1116'] 
>>> string = 'You Score is MX 14.98.' 
>>> evaluate(string, values) 
False 
string = 'You Score is MX 115.' # 115 is not in values 
>>> evaluate(string, values) 
True 

Answer 2

如果你真的需要通过炭去焦炭则：

def evaluate(string, values): 
    value = [] 
    for char in string: 
     if char.isdigit() or char in ',.': 
      value.append(char) 
    value = ''.join(value).strip('.,') 
    return int(value in values) 

测试

>>> values = ['14', '14.98', '114', '114.98', '1,116.5'] 
>>> string = 'You Score is MX 14.98.' 
>>> evaluate(string, values) 
1 
string = 'You Score is MX 115.' # 115 is not in values 
>>> evaluate(string, values) 
0