XPATH找到一个节点，如果没有其他节点具有sertin值

Question

我需要返回所有的书只有疗法是没有书的14.95的价格....

的DTD

<!ELEMENT inventory (book)+> 
<!ELEMENT book (title, author+, publisher+, price, chapter*)> 
<!ATTLIST book num ID #REQUIRED> 
<!ELEMENT chapter (title, (paragraph* | section*))> 
<!ELEMENT section (title?, paragraph*)> 
<!ELEMENT title (#PCDATA)> 
<!ELEMENT author (#PCDATA)> 
<!ELEMENT publisher (#PCDATA)> 
<!ELEMENT price (#PCDATA)> 
<!ATTLIST price currency CDATA #FIXED "usd"> 
<!ELEMENT paragraph (#PCDATA | emph | image)*> 
<!ELEMENT emph (#PCDATA)> 
<!ELEMENT image EMPTY > 
<!ATTLIST image 
      file 
      CDATA #REQUIRED 
      height CDATA #IMPLIED 
      width CDATA #IMPLIED > 

XML例如XML不是约束是这一个

version="1.0" encoding="UTF-8"?> 
<!DOCTYPE inventory SYSTEM "books.dtd"> 
    <inventory> 
     <book num="b1"> 
     <title>Snow Crash</title> 
     <author>Neal Stephenson</author> 
     <publisher>Spectra</publisher> 
     <price>14.95</price> 
     <chapter> 
     <title>Snow Crash - Chapter A</title> 
     <paragraph> 
      This is the 
      <emph>first</emph> 
      paragraph. 
      <image file="firstParaImage.gif"/> 
      After image... 
     </paragraph> 
     <paragraph> 
      This is the 
      <emph>second</emph> 
      paragraph. 
      <image file="secondParaImage.gif"/> 
      After image... 
     </paragraph> 
     </section> 
    </chapter> 
</book> 
<book num="b3"> 
    <title>Zodiac</title> 
    <author>Neal Stephenson</author> 
    <publisher>Spectra</publisher> 
    <price>7.50</price> 
    <chapter> 
     <title>Zodiac - Chapter A</title> 
    </chapter> 
</book> 
</inventory> 

我知道如何寻找所有的书价difrent从14.95 ..但我现在不如何做，如果statment在XPTH 的assigme NT是XPTH只有

Answer 1

这将返回所有的书时，有没有与价格= 14.96：

(//book)[not(//book[price = 14.95])] 

此方法返回的价格= 14.95所有书籍或全部，如果是没有的：

//book[price = 14.95 or not(//book[price = 14.95])] 

如果您的XPath引擎优化得不好，这可能会更快：

(//book)[not(//book[price = 14.95])] | //book[price = 14.95] 

Answer 2

这似乎是最简单的方法在我看来：

/*[not(book/price='14.95')]/book