2017-08-23 55 views
0

每当我提出我的形式来执行PHP脚本,我得到的错误信息后:

Deprecated: Automatically populating $HTTP_RAW_POST_DATA is deprecated and 
will be removed in a future version. To avoid this warning set 'always_populate_raw_post_data' to '-1' in php.ini and use the php://input stream instead. in Unknown on line 0 

Warning: Cannot modify header information - headers already sent in Unknown on line 0 

我有没有注释,并确保它是-1 。我也切换到PHP 7和重新启动我的WAMP的服务器。 php的元素之后我也查空白之前EN。不过,我仍然收到错误消息。

还能是什么可能呢?

的script.php

<?php 
parse_str(file_get_contents("php://input"), $_POST); 
$link = mysqli_connect("127.0.0.1", "root", "", "izandb"); 

if(isset($_POST['submit'])) { 

$klas = $_POST['klasDown']; 
$naam = $_POST['naamTxt']; 
$percentages = $_POST['percentages']; 
$antwoorden = $_POST['antwoorden']; 

$stmt = $link->prepare(' 
INSERT INTO resultaten (Klas, Naam, Percentages, Antwoorden) 
VALUES (?, ?, ?, ?) 
'); 
    $stmt->bind_param('ssss', $klas, $naam, $percentages, $antwoorden); 
    $stmt->execute(); 

    echo "Insertion succeed"; 
} 
+0

'已取消,将在未来的version' =被删除>即可移动到最新版的PHP 7.噢,那伤害 –

+0

@AlivetoDie在某些时候你会尝试只是一切:p – user3660293

+0

https://stackoverflow.com/a/40180889/4248328 –

回答

0

我重新启动我的计算机和它的工作

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