SQL程序选择合并

Question

我的做法是：

create procedure "news" 
as 
select newsdate,COUNT(B.id) as total from news B 
where B.newsyear < GETDATE() 
Group by B.newsdate 

select newsdate,COUNT(B.id) as total from news B 
where B.status='WAITING' and B.cancel='1' 
Group by B.newsdate 

结果：

newsdate total 
2011  4 
2010  8 

newsdate total 
2011  2 
2010  3 

如何合并一年总计获得这个结果集：

newsdate total 
2011  6  {4 + 2} 
2010  11  {8 + 3} 

Answer 1

使用简单或声明（如果它确实是同一个表）：

select newsdate,COUNT(B.id) as total 
from news B 
where B.newsyear < GETDATE() 
    or B.status='WAITING' and B.cancel='1' 
Group by B.newsdate 

，或者使用UNION ALL + Sum聚集（如果它是不同的表）：

select newsdate, sum(total) as total from (
    select newsdate,COUNT(B.id) as total from news B where B.newsyear < GETDATE() 
    Group by B.newsdate 
    union all 
    select newsdate,COUNT(B.id) as total from news B where B.status='WAITING' and B.cancel='1' 
    Group by B.newsdate 
) as rows 
group by newsdate 

Answer 2

试试这个：

select newsdate,COUNT(B.id) as total 
from news B 
where (B.newsyear < GETDATE()) 
or (B.status='WAITING' and B.cancel='1') 
Group by B.newsdate