SQL：在SELECT（存储过程）

Question

写一小部分我有一个SELECT语句如下：

select car.car_ID,isnull(#tmpCount.RowCounter,0) AS RowCounter,ISNULL(#tmpNotServiced.DistinctCounter,0) AS DistinctCounter, ISNULL(#tmpNA.NACounter,0) AS NACounter, (isnull(#tmpCount.RowCounter,0) + ISNULL(#tmpNotServiced.DistinctCounter,0) + ISNULL(#tmpNA.NACounter,0)) AS Total, (CASE ISNULL(#tmpNotServiced.DistinctCounter,0) WHEN 0 THEN 'Closed' ELSE 'Open' END) AS Status 
from car 
left outer join #tmpCount 
on car.AUD_ID = #tmpCount.car_ID 
left outer join #tmpNotServiced 
on car.AUD_ID = #tmpNotServiced.car_ID 
LEFT OUTER JOIN #tmpNA 
ON car.car_ID = #tmpNA.car_ID 

然后一个存储过程[p_GetServiced]计数所有开放和全封闭。

CREATE PROCEDURE [dbo].[p_GetServiced] 

    AS 
    BEGIN 

SET NOCOUNT ON; 

CREATE TABLE #tmp1 
(
    car_ID BIGINT, 
    RowCounter BIGINT, 
    DistinctCounter BIGINT, 
    NACounter BIGINT, 
    Total BIGINT, 
    [Status] VARCHAR(MAX) 
) 
CREATE TABLE #tmp2 (car_ServiceDate DATETIME) 

INSERT INTO #tmp1 
EXEC [p_GetServiceDetail] 

SELECT [Status] AS [Serviced], COUNT(*) AS [Status] FROM #tmp1 
GROUP BY [Status] 


INSERT INTO #tmp2 
SELECT car_TargetDate FROM dbo.car 
END 
GO 

我想让它返回 '服务' 和一小部分（5 2）如：服务（2/5）或NotServiced（3/5）

注：2作为开放和5总行

Answer 1

下应该给你两列，一个用于封闭和一个开放的状态和输出在你想要的格式是两行。

SELECT '[OPEN]', 
CONVERT(NVARCHAR(100), (SELECT COUNT(*) FROM #tmp1 WHERE [Status] = 'OPEN')) + 
' of ' + CONVERT(NVARCHAR(100), COUNT(*)) 
FROM #tmp1 
UNION 
SELECT '[CLOSED]', 
CONVERT(NVARCHAR(100), (SELECT COUNT(*) FROM #tmp1 WHERE [Status] = 'CLOSED')) + 
' of ' + CONVERT(NVARCHAR(100), COUNT(*)) 
FROM #tmp1 

Answer 2

INSERT INTO #tmp1 
EXEC [p_GetServiceDetail] 

DECLARE @TotalRows BIGINT 
SELECT @TotalRows = COUNT(*) FROM #tmp1 

SELECT [Status] AS [Serviced], COUNT(*) AS [Status], @TotalRows AS [Rows] 
FROM #tmp1 
GROUP BY [Status] 

或者，有重读你的问题，我觉得更令人满意的方法是利用OVER条款：

SELECT DISTINCT 
Status 
+ ' (' 
+ CONVERT(VARCHAR, count(*) OVER (PARTITION BY status)) 
+ ' OF ' 
+ CONVERT(VARCHAR, count(*) OVER()) 
+ ')' 
FROM #tmp1 

我们得到以下：

Serviced (1 OF 4) 
NotServiced (3 OF 4)