MySQL查询：数列

Question

大家好，大家好我有一个技术问题，我有记录的表是这样的：

DATE  SIP DURATION TYPE 
2017-02-22 670 9  NO ANSWER 
2017-02-22 670 9  ANSWER 
2017-02-22 670 9  ANSWER 
2017-02-22 671 9  NO ANSWER 

我想有结果是这样的：

SIP DURATION NOANSWER ANSWER 
670  18   1  2 
671  9   1  0 

我“会做这样的查询：

select 
DISTINCT(SIP), 
(select count(*) FROM table where TYPE="ANSWERED") 
(select count(*) FROM table where TYPE="NO ANSWERED") 
from table 

但结果统计所有记录在桌子上，是更好地利用集团的？

，对不起，我的小白:( 感谢时间 马尔科

Answer 1

在这种情况下，它更容易使用GROUP BY有条件SUM和COUNT像下面的例子：

SELECT 
    SIP, 
    SUM(CASE TYPE WHEN 'ANSWER' THEN DURATION ELSE 0 END) AS DURATION, 
    COUNT(CASE WHEN TYPE = 'NO ANSWER' THEN 1 ELSE NULL END) AS NOANSWER, 
    COUNT(CASE WHEN TYPE = 'ANSWER' THEN 1 ELSE NULL END) AS ANSWER 
FROM table_name 
GROUP BY SIP 

演示：http://sqlfiddle.com/#!9/b1142/2/0