无法将按钮属性设置为XSLT转换（C＃）

Question

我正在尝试创建一个接口，该接口允许我选择3个XSLT文件并将它们合并在一起，然后使用XML进行转换。我有一个工作转换代码，我正在为其创建一个用户界面。

转型代码：

public static void Transform(string sXmlPath, string sXslPathBody, string sXslPathHead, string sXslPathFoot, string sXslPathMerged) 
     { 
      try 
      { 
       XNamespace ns = "http://www.w3.org/1999/XSL/Transform"; 

       //load Xml 
       XPathDocument myXPathDoc = new XPathDocument(sXmlPath); 

       //Load Body 
       XElement xslt = XElement.Load(sXslPathBody); 

       //Add Code To Body 
       xslt.AddFirst(new XElement(ns + "include", new XAttribute("href", sXslPathFoot))); 
       xslt.AddFirst(new XElement(ns + "include", new XAttribute("href", sXslPathHead))); 

       XElement body = xslt.Descendants("body").Single(); 

       body.AddFirst(new XElement(ns + "call-template", new XAttribute("name", "Header"))); 
       body.Add(new XElement(ns + "call-template", new XAttribute("name", "Footer"))); 

       //Save Combined File 
       //XElement.Save("c:\temp.xlst"); 
       xslt.Save(sXslPathMerged); 

       XslCompiledTransform myXslTrans = new XslCompiledTransform(); 

       //load Combined File 
       myXslTrans.Load(sXslPathMerged); 

       //Merge XML with Combined File 
       XmlTextWriter myWriter = new XmlTextWriter ("result.html", null); 

       //transform Xml 
       myXslTrans.Transform(myXPathDoc, null, myWriter); 

       myWriter.Close(); 
      } 

      catch (Exception e) 
      { 
       Console.WriteLine("Exception: {0}", e.ToString()); 
      } 
     } 

转换代码工作正常，但我想每个阶段设定一个按钮，可以让我选择任何3个XSLT文件，我想，还有我想要的任何XML 。然后一个按钮将3个XSLT文件合并在一起&创建一个HTML输出。

代码：

public partial class Form1 : Form 
    { 
     String HeadFileSelected, BodyFileSelected, FootFileSelected, XmlFileSelected, MergeFiles; 

     public Form1() 
     { 
      InitializeComponent(); 
     } 

     //Head 
     private void openFileHead_FileOk(object sender, CancelEventArgs e) 
     { 

     } 

     private void header_Click(object sender, System.EventArgs e) 
     { 
      if (openFileHead.ShowDialog() == System.Windows.Forms.DialogResult.OK) 
      { 
       HeadFileSelected = openFileHead.FileName; 

       string filename = HeadFileSelected; 

       textBox2.Text = HeadFileSelected; 
      } 
     } 

     //Body 
     private void openFileBody_FileOk(object sender, CancelEventArgs e) 
     { 

     } 

     private void body_Click(object sender, System.EventArgs e) 
     { 
      if (openFileBody.ShowDialog() == System.Windows.Forms.DialogResult.OK) 
      { 
       BodyFileSelected = openFileBody.FileName; 

       string filename = BodyFileSelected; 

       textBox3.Text = BodyFileSelected; 
      } 
     } 

     //Foot 
     private void openFileFooter_FileOk(object sender, CancelEventArgs e) 
     { 

     } 

     private void footer_Click(object sender, System.EventArgs e) 
     { 
      if (openFileFooter.ShowDialog() == System.Windows.Forms.DialogResult.OK) 
      { 
       FootFileSelected = openFileFooter.FileName; 

       string filename = FootFileSelected; 

       textBox4.Text = FootFileSelected; 
      } 
     } 

     //Xml 
     private void openFileXml_FileOk(object sender, CancelEventArgs e) 
     { 

     } 

     private void xml_Click(object sender, System.EventArgs e) 
     { 
      if (openFileXml.ShowDialog() == System.Windows.Forms.DialogResult.OK) 
      { 
       XmlFileSelected = openFileXml.FileName; 
      } 
     } 

     //Merge 
     private void openFileMerge_FileOk(object sender, CancelEventArgs e) 
     { 

     } 

     private void merge_Click(object sender, EventArgs e) 
     { 

      //XmlTransformUtil objXMLTrans = new XmlTransformUtil(); 
      XmlTransformUtil.Transform(XmlFileSelected, BodyFileSelected, HeadFileSelected, FootFileSelected, MergeFiles); 
     } 
    } 

我已成功地获得XML选择& 3个XSLT选择做工精细，它只是不工作，因为我无法将其归因合并按钮的String MergeFiles;到Transform(string sXslPathMerged)

我明白为什么它不起作用，但我现在不能解决这个问题，它会给我带来我需要的结果。

Answer 1

为了解决这个问题，我需要将MergeFiles定义为保存的XSLT，因为它是空的，所以它不会去任何地方。在我的表单中添加了以下内容。

MergeFiles = "C:\\Users\\user\\Desktop\\TEMP.xslt";