如果你是开放的TVF(表值函数)。
厌倦提取字符串(CHARINDEX,左,右,...)我修改解析函数接受两个不一样的分隔符。在你的情况下,这将是(和)。
例
Declare @YourTable table (ID int,SomeCol varchar(max))
Insert Into @YourTable values
(1,'blablablablalbaalala (blibliblobloblo) blalblalala (blululublululu)')
Select A.ID
,B.*
From @YourTable A
Cross Apply [dbo].[udf-Str-Extract](A.SomeCol,'(',')') B
返回
ID RetSeq RetPos RetVal
1 1 23 blibliblobloblo
1 2 53 blululublululu
的UDF如果有兴趣
CREATE FUNCTION [dbo].[udf-Str-Extract] (@String varchar(max),@Delimiter1 varchar(100),@Delimiter2 varchar(100))
Returns Table
As
Return (
with cte1(N) As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
cte2(N) As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 N1,cte1 N2,cte1 N3,cte1 N4,cte1 N5,cte1 N6) A),
cte3(N) As (Select 1 Union All Select t.N+DataLength(@Delimiter1) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter1)) = @Delimiter1),
cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter1,@String,s.N),0)-S.N,8000) From cte3 S)
Select RetSeq = Row_Number() over (Order By N)
,RetPos = N
,RetVal = left(RetVal,charindex(@Delimiter2,RetVal)-1)
From (
Select *,RetVal = Substring(@String, N, L)
From cte4
) A
Where charindex(@Delimiter2,RetVal)>1
)
/*
Max Length of String 1MM characters
Declare @String varchar(max) = 'Dear [[FirstName]] [[LastName]], ...'
Select * From [dbo].[udf-Str-Extract] (@String,'[[',']]')
*/
什么版本的SQL Server? 2016或更早? – gbn
检查了这一点https://stackoverflow.com/questions/4843121/how-to-extract-multiple-strings-from-single-rows-in-sql-server –
您是否在寻找文本包含括号'[]'或圆括号'()'? – Jason