在iPhone应用程序中如何检测设备的屏幕分辨率

Question

在iPhone应用程序中， 在设备上运行应用程序时如何检测运行App的设备的屏幕分辨率？

Answer 1

CGRect screenBounds = [[UIScreen mainScreen] bounds]; 

这会给你整个屏幕的分辨率分，所以这将最典型的为320x480像素的iPhone。尽管iPhone4拥有更大的屏幕尺寸，但iOS仍然支持320x480而不是640x960。这主要是因为较旧的应用程序中断。

CGFloat screenScale = [[UIScreen mainScreen] scale]; 

这会给你屏幕的比例。对于没有视网膜显示器的所有设备，这将返回1.0f，而Retina显示设备将提供2.0f，iPhone 6 Plus（Retina HD）将提供3.0f。

现在，如果你想获得像素宽度&高度的iOS设备屏幕，你只需要做一件简单的事情。

CGSize screenSize = CGSizeMake(screenBounds.size.width * screenScale, screenBounds.size.height * screenScale); 

通过乘以屏幕的比例可以得到实际的像素分辨率。

关于iOS中点和像素之间的区别，可以阅读here。

编辑：（版本为SWIFT）

let screenBounds = UIScreen.main.bounds 
let screenScale = UIScreen.main.scale 
let screenSize = CGSize(width: screenBounds.size.width * screenScale, height: screenBounds.size.height * screenScale) 

Answer 2

见UIScreen参考：http://developer.apple.com/library/ios/#documentation/uikit/reference/UIScreen_Class/Reference/UIScreen.html

if([[UIScreen mainScreen] respondsToSelector:NSSelectorFromString(@"scale")]) 
{ 
    if ([[UIScreen mainScreen] scale] < 1.1) 
     NSLog(@"Standard Resolution Device"); 

    if ([[UIScreen mainScreen] scale] > 1.9) 
     NSLog(@"High Resolution Device"); 
} 

Answer 3

使用它在应用代表：我用故事板

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions{ 

if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) { 

    CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size; 

    //----------------HERE WE SETUP FOR IPHONE 4/4s/iPod---------------------- 

    if(iOSDeviceScreenSize.height == 480){   

     UIStoryboard *iPhone35Storyboard = [UIStoryboard storyboardWithName:@"iPhone" bundle:nil]; 

     // Instantiate the initial view controller object from the storyboard 
     UIViewController *initialViewController = [iPhone35Storyboard instantiateInitialViewController]; 

     // Instantiate a UIWindow object and initialize it with the screen size of the iOS device 
     self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]]; 

     // Set the initial view controller to be the root view controller of the window object 
     self.window.rootViewController = initialViewController; 

     // Set the window object to be the key window and show it 
     [self.window makeKeyAndVisible]; 

     iphone=@"4"; 

     NSLog(@"iPhone 4: %f", iOSDeviceScreenSize.height); 

    } 

    //----------------HERE WE SETUP FOR IPHONE 5---------------------- 

    if(iOSDeviceScreenSize.height == 568){ 

     // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4 
     UIStoryboard *iPhone4Storyboard = [UIStoryboard storyboardWithName:@"iPhone5" bundle:nil]; 

     // Instantiate the initial view controller object from the storyboard 
     UIViewController *initialViewController = [iPhone4Storyboard instantiateInitialViewController]; 

     // Instantiate a UIWindow object and initialize it with the screen size of the iOS device 
     self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]]; 

     // Set the initial view controller to be the root view controller of the window object 
     self.window.rootViewController = initialViewController; 

     // Set the window object to be the key window and show it 
     [self.window makeKeyAndVisible]; 

     NSLog(@"iPhone 5: %f", iOSDeviceScreenSize.height); 
     iphone=@"5"; 
    } 

} else if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) { 
    // NSLog(@"wqweqe"); 
    storyboard = [UIStoryboard storyboardWithName:@"iPad" bundle:nil]; 

} 

return YES; 
} 

Answer 4

对于iOS 8，我们可以只使用这个[UIScreen mainScreen].nativeBounds，这样的：

- (NSInteger)resolutionX 
{ 
    return CGRectGetWidth([UIScreen mainScreen].nativeBounds); 
} 

- (NSInteger)resolutionY 
{ 
    return CGRectGetHeight([UIScreen mainScreen].nativeBounds); 
} 

Answer 5

UIScreen类让你找到屏幕点和像素的解决方案。

屏幕分辨率是以点或像素来衡量的。它不应该与屏幕大小混淆。较小的屏幕尺寸可以具有较高的分辨率。

UIScreen在积分

UIScreen的“nativeBounds.width”返回的矩形尺寸在Pixels.This值“bounds.width”返回的矩形尺寸被检测为PPI（每英寸点）。显示设备上图像的清晰度&。

您可以使用UIScreen类来检测所有这些值。

Swift3

// Normal Screen Bounds - Detect Screen size in Points. 
let width = UIScreen.main.bounds.width 
let height = UIScreen.main.bounds.height 
print("\n width:\(width) \n height:\(height)") 

// Native Bounds - Detect Screen size in Pixels. 
let nWidth = UIScreen.main.nativeBounds.width 
let nHeight = UIScreen.main.nativeBounds.height 
print("\n Native Width:\(nWidth) \n Native Height:\(nHeight)") 

控制台

width:736.0 
height:414.0 

Native Width:1080.0 
Native Height:1920.0 

夫特2.x的

//Normal Bounds - Detect Screen size in Points. 
    let width = UIScreen.mainScreen.bounds.width 
    let height = UIScreen.mainScreen.bounds.height 

// Native Bounds - Detect Screen size in Pixels. 
    let nWidth = UIScreen.mainScreen.nativeBounds.width 
    let nHeight = UIScreen.mainScreen.nativeBounds.height 

的ObjectiveC

// Normal Bounds - Detect Screen size in Points. 
CGFloat *width = [UIScreen mainScreen].bounds.size.width; 
CGFloat *height = [UIScreen mainScreen].bounds.size.height; 

// Native Bounds - Detect Screen size in Pixels. 
CGFloat *width = [UIScreen mainScreen].nativeBounds.size.width 
CGFloat *height = [UIScreen mainScreen].nativeBounds.size.width 

Answer 6

使用此代码，这将有助于获得设备的屏幕分辨率的任何类型的

[[UIScreen mainScreen] bounds].size.height 
[[UIScreen mainScreen] bounds].size.width