连接到服务器http客户端

try{ 
       HttpClient httpclient = new DefaultHttpClient(); 
       HttpPost httppost = new HttpPost("http://nayyar.5gbfree.com/welcome.php"); 
       httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 
       HttpResponse response = httpclient.execute(httppost); 
       HttpEntity entity = response.getEntity(); 
       is = entity.getContent(); 

       Log.e("log_tag", "connection success "); 
Toast.makeText(getApplicationContext(), "pass", Toast.LENGTH_SHORT).show(); 
      }

我试图第一次连接到服务器。我从互联网复制代码尝试执行。但总是在nameValuePairs上显示错误。我不知道这是什么。以及为什么错误是。有人向我解释代码和错误，或者解释我通过代码以他/她自己的方式连接到服务器。应该非常感激。连接到服务器http客户端

来源

2014-03-13 Roshaan Nayyar

不，我们不会给你code_。当你用你写的代码发布问题时，**总是**陈述你的目标。如果有错误，**总是**发布堆栈跟踪或编译器错误。或者解释一下你的期望如何表现。 –

这意味着，你应该声明那些nameValuePairs！ –

错误：nameValuePairs无法解析为变量 –

你必须做出的NameValuePair列表...这样

HttpClient httpclient = new DefaultHttpClient(); 
HttpPost httppost = new HttpPost("http://nayyar.5gbfree.com/welcome.php"); 
List<NameValuePair> postParameters = new ArrayList<NameValuePair>(); 
UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(
        postParameters); 
httppost.setEntity(formEntity); 
HttpResponse response = httpclient.execute(httppost);

，然后得到这样

BufferedReader br = new BufferedReader(new InputStreamReader(
        httppost.getEntity().getContent())); 

br.readLine(); // Save it in a String variable or whatever you want

来源

2014-03-13 17:58:12

哪些数据必须得到您的POST数据？例如，如果url需要“id”和“user”：

HttpClient httpclient = new DefaultHttpClient(); 
HttpPost httppost = new HttpPost("http://nayyar.5gbfree.com/welcome.php"); 

      // Add your data 
      List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2); 
      nameValuePairs.add(new BasicNameValuePair("id", "12345")); 
      nameValuePairs.add(new BasicNameValuePair("user", "Jorgesys!")); 

httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 
    ... 
    ... 
    ...

来源

2014-03-13 17:58:29 Jorgesys

连接到服务器http客户端

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