为什么我不能转换的inputed字符串到变量

Question

我都提到了这个问题，在论坛上这样做： Using a string as a variable at run time

这是我有：

def create_account 
    puts "Username?" 
    account_name=gets.chomp 
    account_name_var=#account_name as variable 

    #Sets array as variable 
    string_values = { } 
    some_string = [:some_string]  # parameter was, say "Hello" 
    string_values[some_string] = account_name 
    string_values       # { 'Hello' => 42 } 
    account_name_var = string_values[some_string] 
    account_name_var        # 42 

    account_name_var=BankAccount.new(account_name, "open") 
    account_name_var=BankAccount.new(account_name, "open") 
end 

create_account 
create_account 
# pablo=BankAccount.new("pablo", "open") 
# theo=BankAccount.new("theo", "open") 
make_transfer(name, name2, 10) 

，但我得到

：用于主未定义局部变量或方法名称：对象 （NameError）就行了make_transfer（姓名，NAME2 10）

。

因此，当我输入name作为第一个用户名和name2作为第二个用户名时，name未被设置为变量。

Answer 1

刚刚从你的方法返回BankAccount实例，并将其赋值给一个变量：

def create_account 
    puts "Username?" 
    account_name = gets.chomp 
    BankAccount.new(account_name, "open") 
end 

account_1 = create_account 
account_2 = create_account 
make_transfer(account_1, account_2, 10) 

或者，使用Hash按名称帐户存储：

@accounts = {} 

account = create_account 
@accounts[account.name] = account 

account = create_account 
@accounts[account.name] = account 

make_transfer(@accounts['pablo'], @accounts['theo'], 10)